22.

(a) We obtain

ω =

(200 rev/min)(2π rad/rev)

60 s/min

= 20.9 rad/s .

(b) With r = 1.20/2 = 0.60 m, Eq. 11-18 leads to

v = rω = (0.60)(20.9) = 12.6 m/s .

(c) With t = 1 min, ω = 1000 rev/min and ω

o

= 200 rev/min, Eq. 11-12 gives

α =

ω

− ω

o

t

= 800 rev/min

2

.

(d) With the same values used in part (c), Eq. 11-15 becomes

θ =

1

2

(ω

o

+ ω) t =

1

2

(200 + 1000) (1) = 600 rev .