P29 019

background image

19.

(a) The frequency of revolution is

f =

Bq

2πm

e

=

(35.0

× 10

6

T)(1.60

× 10

19

C)

2π(9.11

× 10

31

kg)

= 9.78

× 10

5

Hz .

(b) Using Eq. 29-16, we obtain

r =

m

e

v

qB

=

2m

e

K

qB

=



2(9.11

× 10

31

kg)(100 eV)(1.60

× 10

19

J/eV)

(1.60

× 10

19

C)(35.0

× 10

6

T)

= 0.964 m .


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