95. (Third problem of Cluster)

(a) Using the junction rule (i

1

= i

2

+ i

3

) we write two loop rule equations:

E

1

− i

2

R

2

− (i

2

+ i

3

) R

1

=

0

E

2

− i

3

R

3

− (i

2

+ i

3

) R

1

=

0 .

Solving, we find i

2

= 0.0109 A (rightward, as was assumed in writing the equations as we did),

i

3

= 0.0273 A (leftward), and i

1

= i

2

+ i

3

= 0.0382 A (downward).

(b) See the results in part (a).

(c) See the results in part (a).

(d) The voltage across R

1

equals V

A

: (0.0382 A)(100 Ω) = +3.82 V.