60.

(a) The equivalent capacitance is

C

eq

=

C

1

C

2

C

1

+ C

2

=

(6.00 µF)(4.00 µF)

6.00 µF + 4.00 µF

= 2.40 µF .

(b) q = C

eq

V = (2.40 µF)(200 V) = 4.80

× 10

4

C.

(c) V

1

= q/C

1

= 4.80

× 10

4

C/2.40 µF = 120 V, and V

2

= V

− V

1

= 200 V

− 120 V = 80 V.