out ABDHPEJT


argc: 19 Obtained scalar parameters: m_mode: 1 m_cn: 8 m_n: 8 m_size: 9 exp_arg_count: 19 Mapping: i=1, m_map[i]='A' i=2, m_map[i]='B' i=3, m_map[i]='D' i=4, m_map[i]='H' i=5, m_map[i]='P' i=6, m_map[i]='E' i=7, m_map[i]='J' i=8, m_map[i]='T' Inverse mapping: key='A', value=1 key='B', value=2 key='D', value=3 key='E', value=6 key='H', value=4 key='J', value=7 key='P', value=5 key='T', value=8 Constant (long format) ( t=0, i=1, first=1, k=12, argc=19, prev=A, next=B t=0, i=2, first=1, k=13, argc=19, prev=B, next=D t=0, i=3, first=1, k=14, argc=19, prev=D, next=H t=0, i=4, first=1, k=15, argc=19, prev=H, next=P t=0, i=5, first=1, k=16, argc=19, prev=P, next=E t=0, i=6, first=1, k=17, argc=19, prev=E, next=J t=0, i=7, first=1, k=18, argc=19, prev=J, next=T t=0, i=8, first=1, k=19, argc=19, prev=T, next=A B, D, H, P, E, J, T, A, ) ### Involution 0: ID=1, algo=1 a=(A)(B, T)(D, J)(H, E)(P) b=(A, B)(D, T)(H, J)(P, E) ### Involution 1: ID=2, algo=1 a=(A, B)(D, T)(H, J)(P, E) b=(A, D)(B)(H, T)(P, J)(E) ### Involution 2: ID=3, algo=1 a=(A, D)(B)(H, T)(P, J)(E) b=(A, H)(B, D)(P, T)(E, J) ### Involution 3: ID=4, algo=1 a=(A, H)(B, D)(P, T)(E, J) b=(A, P)(B, H)(D)(E, T)(J) ### Involution 4: ID=5, algo=1 a=(A, P)(B, H)(D)(E, T)(J) b=(A, E)(B, P)(D, H)(J, T) ### Involution 5: ID=6, algo=1 a=(A, E)(B, P)(D, H)(J, T) b=(A, J)(B, E)(D, P)(H)(T) ### Involution 6: ID=7, algo=1 a=(A, J)(B, E)(D, P)(H)(T) b=(A, T)(B, J)(D, E)(H, P) ### Involution 7: ID=8, algo=1 a=(A, T)(B, J)(D, E)(H, P) b=(A)(B, T)(D, J)(H, E)(P) >>>>> Method 1 found 8 results >>>>> Found 0 duplicates >>>>> All results ### Result 1 ### ID=1, algo=1 a=(A)(B, T)(D, J)(H, E)(P) b=(A, B)(D, T)(H, J)(P, E) ### Result 2 ### ID=2, algo=1 a=(A, B)(D, T)(H, J)(P, E) b=(A, D)(B)(H, T)(P, J)(E) ### Result 3 ### ID=3, algo=1 a=(A, D)(B)(H, T)(P, J)(E) b=(A, H)(B, D)(P, T)(E, J) ### Result 4 ### ID=4, algo=1 a=(A, H)(B, D)(P, T)(E, J) b=(A, P)(B, H)(D)(E, T)(J) ### Result 5 ### ID=5, algo=1 a=(A, P)(B, H)(D)(E, T)(J) b=(A, E)(B, P)(D, H)(J, T) ### Result 6 ### ID=6, algo=1 a=(A, E)(B, P)(D, H)(J, T) b=(A, J)(B, E)(D, P)(H)(T) ### Result 7 ### ID=7, algo=1 a=(A, J)(B, E)(D, P)(H)(T) b=(A, T)(B, J)(D, E)(H, P) ### Result 8 ### ID=8, algo=1 a=(A, T)(B, J)(D, E)(H, P) b=(A)(B, T)(D, J)(H, E)(P) >>>>> All results (OpenOffice equation) bold a_1~=~(A)(B, T)(D, J)(H, E)(P) newline bold b_1~=~(A, B)(D, T)(H, J)(P, E) newline newline bold a_2~=~(A, B)(D, T)(H, J)(P, E) newline bold b_2~=~(A, D)(B)(H, T)(P, J)(E) newline newline bold a_3~=~(A, D)(B)(H, T)(P, J)(E) newline bold b_3~=~(A, H)(B, D)(P, T)(E, J) newline newline bold a_4~=~(A, H)(B, D)(P, T)(E, J) newline bold b_4~=~(A, P)(B, H)(D)(E, T)(J) newline newline bold a_5~=~(A, P)(B, H)(D)(E, T)(J) newline bold b_5~=~(A, E)(B, P)(D, H)(J, T) newline newline bold a_6~=~(A, E)(B, P)(D, H)(J, T) newline bold b_6~=~(A, J)(B, E)(D, P)(H)(T) newline newline bold a_7~=~(A, J)(B, E)(D, P)(H)(T) newline bold b_7~=~(A, T)(B, J)(D, E)(H, P) newline newline bold a_8~=~(A, T)(B, J)(D, E)(H, P) newline bold b_8~=~(A)(B, T)(D, J)(H, E)(P) newline newline

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