XMLElement getChildren





XMLElement::getChildren() \ Language (API) \ Processing 1.0
























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Reference for Processing version 1.0+. If you have a previous version, use the reference included with your software. If you see any errors or have any comments, let us know.

Class XMLElement Name getChildren() Examples // The following short XML file called "sites.xml" is parsed // in the code below. It must be in the project's "data" directory // <?xml version="1.0"?> // <websites> // <site id="0" url="processing.org">Processing</site> // <site id="1" url="mobile.processing.org">Processing Mobile</site> // </websites< XMLElement xml; void setup() { size(200, 200); xml = new XMLElement(this, "sites.xml"); XMLElement[] kids = xml.getChildren(); for (int i=0; i < kids.length; i++) { String site = kids[i].getContent(); println(site); } }void setup() { // Download RSS feed of news stories from yahoo.com String url = "http://rss.news.yahoo.com/rss/topstories"; XMLElement rss = new XMLElement(this, url); // Get all elements XMLElement[] links = rss.getChildren("channel/item/link"); for (int i = 0; i < links.length; i++) { println(links[i].getContent()); } } Description Returns all of the children as an XMLElement array. When the path parameter is specified, then it will return all children that match that path. The path is a series of elements and sub-elements, separated by slashes. Syntax xml.getChildren() xml.getChildren(path) Parameters xml any variable of type XMLElement Returns XMLElement[] Usage Web & Application Related XMLElement_getChildCount()XMLElement_getChild()

Updated on February 26, 2009 08:28:43pm PST












Processing was initiated by Ben Fry and Casey Reas. It is developed by a small team of volunteers.


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