$$w_{K} = \frac{\Sigma_{\text{fi}}}{100}x\frac{\rho_{k}}{\rho_{\text{kn}}} = \frac{3,152}{100}x\frac{2,9}{2,65} = 0,035$$

$$m = \frac{C}{W} = \frac{f_{\text{co}}}{A_{1}} + 0,5 = \frac{48,1}{26} + 0,5 = 2,35$$

$$m = \frac{C}{W} = \frac{f_{\text{co}}}{A_{1}} + 0,5 = \frac{48,1}{26} - 0,5 = 1,35$$

$$C = \frac{1000}{\frac{1}{m}\left( 1 + \frac{1 - w_{c}m}{w_{k}\rho_{k}} \right) + \frac{1}{\rho_{c}}} = \frac{1000}{\frac{1}{2,35}\left( 1 + \frac{1 - 0,25 \times 2,35}{0,035 \times 2,90} \right) + \ \frac{1}{3,10}} = \frac{1000}{2,48} = 403,23\ kg/m^{3}$$

$$K = \frac{c(1 - w_{c}m)}{w_{k}m} = \ \frac{403,23\ (1 - 0,25 \times 2,35)}{0,035 \times 2,35} = 2022,28\ kg/m^{3}$$

$$W = \frac{C}{m} = \frac{403,23}{2,35} = 171,59\ kg/\ m^{3}$$