$$\frac{1}{T_{\text{rz}}} = \frac{1}{T_{\text{cz}}} + \frac{\lambda}{C_{2}}\ln A$$

C₂ = 1, 44x10⁻²  m • K ∖ nλ = 650 nm

[K] = [ + 273]

P = U • I

$$P = \left| \frac{\text{δP}}{\text{δU}} \right|U + \left| \frac{\text{δP}}{\text{δI}} \right|I = I \bullet U + U \bullet I$$

$$U = \frac{klasa \bullet zakres}{100} = \frac{3 \bullet 7500}{100} = 0,225\ A \approx 0,23\ A$$

$$I = \frac{klasa \bullet zakres}{100} = \frac{2 \bullet 10}{100} = 0,2\ V$$

P = U • I

$$P = \left| \frac{\text{δP}}{\text{δU}} \right|U + \left| \frac{\text{δP}}{\text{δI}} \right|I = I \bullet U + U \bullet I$$