23 (287)

23 (287)



For such markinss M. it has to be shown that:

1.    M(s4) = 0 (i.e. channel is empty)

From irwariant i3 we have:

M(s4) + M(s5) + n*M(s9) = n

Now, M(s4) <= 0, M(s5) >= n, M(s9) >= 0 (YES, the channel is empty - s4)

2.    M(s3) >= 1 (i.e. Sender is Inactive)

Combining invariants i4 and i6 (Sender Inactive s3 + termination of messages - s6) together we get:

[M(s6) + M(sl2) + M(sl 1) - M(s3) - 0]    M(s3) >= M(s6) >= 1


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