File0036 (6)

Dane:

T= ls h = 200m R = 6,37* 10^A6 m

Szukane:

AT=?

mg = GmM / R² g = GM / R²

mg’ = GmM / (R+h)^: g’ = GM / (R+h)²

T/T = (2n V(l/g)) / (2ii V(l/g’)) = V(lg7gl) = V(g7g) g7 g = GM/(R+h)² * R²/(GM) = R²/(R+h)

[sm/m = s]

T/T= R / (R+h) T’R= T(R+h) T’= T(R+h)/R

T’= 1 *(6,37* 10^A6+200) / (6,37* 10^A6) = 1,00003 s AT= T’ - T

AT= 1.00003-1 =0,00003 s

Odp. Zegar umieszczony na wysokości 200m opóźnia się o 0,00003 s. Zadanie 4.

Zadanie 5.

Dane    Szukane

V=5000 m/s    Y = ?

L= 1,54 ni A(p= cp/2

\=V/y

y=V/ X f (m/s)/m= 1/s = Hz]

Aip = 271 (d/ X)

(p/2 = 2tt (1/ X)

(p = 4n (1/ X)

X= 4n 1 / <p (p= tc przy normalnym obiegu

31=41