background image

 

 

 

 

Project “The development of the didactic potential of Cracow University of Technology in the range of modern 

construction” is co-financed by the European Union within the confines of the European Social Fund  

and realized under surveillance of Ministry of Science and Higher Education. 

1

Exercise 4.3 

 

10 kN

16 kNm

2

2 kN

q

2

=2 kN/m

q

1

=4 kN/m

O

2m

2m

6m

4m

=2 kN/m2

=2 kN/m2

45°

 

 

Given the structure  shown above

 

I. 

Check if the  force system acting on it can be reduced to the resultant force. 

II. 

If yes, determine whether the central axis passes through point O. 

 
 
 

                                  

I

 

The necessary and sufficient condition for a reduction of a planar force system to a resultant force states  
that the sum  vector must be different from zero. 
 

F

3

=10 kN

M

1

=16 kNm

2

2 kN

q

2

=2 kN/m

q

1

=4 kN/m

O

2m

2m

4m

=2 kN/m2

=2 kN/m2

45°

W

4

W

3

W

2

W

1

3m

3m

F

2

F

1

 

 
 

background image

 

 

 

 

Project “The development of the didactic potential of Cracow University of Technology in the range of modern 

construction” is co-financed by the European Union within the confines of the European Social Fund  

and realized under surveillance of Ministry of Science and Higher Education. 

2

  Replacing  the distributed loads by their resultants. 

]

[

6

]

[

6

])

/

[

2

]

/

[

4

(

2

1

1

kN

m

m

kN

m

kN

W

 

]

[

12

]

[

6

]

/

[

2

2

kN

m

m

kN

W

 

]

[

24

]

[

12

]

/

[

2

2

2

3

kN

m

m

kN

W

 

]

[

32

]

[

16

]

/

[

2

2

2

4

kN

m

m

kN

W

 

 

  Resolving the oblique forces into components 

]

[

2

2

)

45

cos(

1

kN

F

,  

]

[

2

2

)

45

sin(

2

kN

F

]

[

2

2

1

kN

F

F

 

 

  Determining the sum vector 

)

,

,

(

O

S

S

S

y

x

 

4

3

1

W

F

F

S

x

 

 

 

]

[

44 kN

S

x

3

2

1

2

W

W

W

F

S

y

      

                     

]

[

40 kN

S

y

)

],

[

40

],

[

44

(

O

kN

kN

S

 

 

0

0

k

S

  

 

  Answer  
 
The system of forces can be reduced to the resultant force

 

 
 

II.

 

If the central axis of the system passes through point O, than the total moment of the system about this point 

must be equal to zero.  

0

O

M

.  

  Determining the total moment about point O 

 
 

)

,

0

,

0

(

Oz

O

M

M

  

]

[

0

]

[

16

]

[

2

]

[

32

]

[

3

]

[

24

]

[

3

]

[

12

]

[

4

]

[

6

]

[

4

]

[

10

]

[

6

]

[

2

kNm

kNm

m

kN

m

kN

m

kN

m

kN

m

kN

m

kN

M

Oz

 

 

)

0

,

0

,

0

(

O

M

 

 

  Answer   
 

Point O lies on the central axis of the system.