P28 065

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65. When all the batteries are connected in parallel, each supplies a current i; thus, i

R

= N i. Then from

E = ir + i

R

R = ir + N ir, we get i

R

= N

E/[(N + 1)r]. When all the batteries are connected in series,

i

r

= i

R

and

E

total

= N

E = Ni

r

r + i

R

R = N i

R

r + i

R

r, so i

R

= N

E/[(N + 1)r].


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