p13 048

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48.

(a) Computing the torques about the hinge, we have

T L sin 40

= W

L

2

sin 50

where the length of the beam is L = 12 m andthe tension is T = 400 N. Therefore, the weight is
W = 671 N.

(b) Equilibrium of horizontal andvertical forces yields, respectively,

F

hinge x

=

T = 400 N

F

hinge y

=

W

670 N

where the hinge force components are rightward(for x) andupward(for y).


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