22.
(a) We obtain
ω =
(200 rev/min)(2π rad/rev)
60 s/min
= 20.9 rad/s .
(b) With r = 1.20/2 = 0.60 m, Eq. 11-18 leads to
v = rω = (0.60)(20.9) = 12.6 m/s .
(c) With t = 1 min, ω = 1000 rev/min and ω
o
= 200 rev/min, Eq. 11-12 gives
α =
ω
− ω
o
t
= 800 rev/min
2
.
(d) With the same values used in part (c), Eq. 11-15 becomes
θ =
1
2
(ω
o
+ ω) t =
1
2
(200 + 1000) (1) = 600 rev .