p36 084

background image

84. We infer from Sample Problem 36-2, that (with angle in radians)

θ =

λ

d

for adjacent fringes. With the wavelength change (λ



= λ/n by Eq. 36-8), this equation becomes

θ



=

λ



d

.

Dividing one equation by the other, the requirement of radians can now be relaxed and we obtain

θ



θ

=

λ



λ

=

1

n

.

Therefore, with n = 1.33 and ∆θ = 0.30

, we find ∆θ



= 0.23

.


Document Outline


Wyszukiwarka

Podobne podstrony:
p36 046
p36 058
PaVeiTekstB 084
p36 054
P31 084
12 2005 083 084
p36 015
p36 018
p36 009
p36 003
ep 12 084
p36 025
p36 017
p36 010
p36 069
p36 056

więcej podobnych podstron