P21 058

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58. Since the volume of the monatomic ideal gas is kept constant it does not do any work in the heating

process. Therefore the heat Q it absorbs is equal to the change in its inertial energy: dQ = dE

int

=

3
2

nR dT . Thus

S

=



dQ

T

=



T

f

T

i

(3nR/2)dT

T

=

3

2

nR ln



T

f

T

i



=

3

2

(1.0 mol)



8.31

J

mol

· K



ln



400 K

300 K



= 3.59 J/K .


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