p09 048

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48.

(a) The thrust is Rv

rel

where v

rel

= 1200 m/s. For this to equal the weight M g where M = 6100 kg,

we must have R = (6100)(9.8)/1200

50 kg/s.

(b) Using Eq. 9-42 with the additional effect due to gravity, we have

Rv

rel

− Mg = Ma

so that requiring a = 21 m/s

2

leads to R = (6100)(9.8 + 21)/1200 = 1.6

× 10

2

kg/s.


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