p11 044

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44.

(a) Using Table 11-2(c) and Eq. 11-27, the rotational kinetic energy is

K

=

1

2

2

=

1

2



1

2

M R

2



ω

2

=

1

4

(500 kg)(200π rad/s)

2

(1.0m)

2

=

4.9

× 10

7

J .

(b) We solve P = K/t (where P is the average power) for the operating time t.

t =

K

P

=

4.9

× 10

7

J

8.0

× 10

3

W

= 6.2

× 10

3

s

which we rewrite as t

100 min.


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