76. Consider the object of mass m

1

falling through a distance h. The loss of its mechanical energy is

∆E = m

1

gh. This amount of energy is then used to heat up the temperature of water of mass m

2

:

∆E = m

1

gh = Q = m

2

c∆T . Thus, the maximum possible rise in water temperature is

∆T

=

m

1

gh

m

2

c

=

(6.00 kg)

9.8 m/s

2



(50.0 m)

(0.600 kg)

4190 J/kg

·C

◦



=

1.17 C

◦

.