76. Consider the object of mass m
1
falling through a distance h. The loss of its mechanical energy is
∆E = m
1
gh. This amount of energy is then used to heat up the temperature of water of mass m
2
:
∆E = m
1
gh = Q = m
2
c∆T . Thus, the maximum possible rise in water temperature is
∆T
=
m
1
gh
m
2
c
=
(6.00 kg)
9.8 m/s
2
(50.0 m)
(0.600 kg)
4190 J/kg
·C
◦
=
1.17 C
◦
.