P15 079

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79. We consider the can with nearly its total volume submerged, and just the rim above water. For calculation

purposes, we take its submerged volume to be V = 1200 cm

3

. To float, the total downward force of gravity

(acting on the tin mass m

t

and the lead mass m



) must be equal to the buoyant force upward:

(m

t

+ m



) g = ρ

w

V g

=

⇒ m



=



1 g/cm

3

 

1200 cm

3



130g

which yields 1070 g for the (maximum) mass of the lead (for which the can still floats). The given density
of lead is not used in the solution.


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