p39 021

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21. The speed v of the electron satisfies K

max

=

1
2

m

e

v

2

=

1
2

(m

e

c

2

)(v/c)

2

= E

photon

Φ. Using Table 38-3,

we find

v = c



2(E

photon

Φ)

m

e

c

2

= (2.998

× 10

8

m/s)



2(5.80 eV

4.50 eV)

511

× 10

3

eV

= 6.76

× 10

5

m/s .


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