p08 040

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40. Since the speed is constant ∆K = 0 and Eq. 8-31 (an application of the energy conservation concept)

implies

W

applied

= ∆E

th

= ∆E

th (cube)

+ ∆E

th (floor)

.

Thus, if W

applied

= (15)(3.0) = 45 J, and we are told that ∆E

th (cube)

= 20 J, then we conclude that

E

th (floor)

= 25 J.


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