p02 088

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88. We assume v

0

= 0 and integrate the acceleration to find the velocity. In the graphs below (the first is

the acceleration, like Fig. 2-35 but with some numbers we adopted, and the second is the velocity) we
modeled the curve in the textbook with straight lines and circular arcs for the rounded corners, and
literally integrated it. The intent of the textbook was not, however, to go through such an involved
procedure, and one should be able to obtain a close approximation to the shape of the velocity graph
below (the one on the right) just by applying the idea that constant nonzero acceleration means a linearly
changing velocity.

–0.4

–0.2

0

0.2

0.4

0.6

0.8

1

t

–0.2

0

0.2

v

t


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