p03 030

background image

30. We consider all possible products and then simplify using relations such as ˆi

· ˆk = 0 and ˆi· ˆi = 1. Thus,

a

·b =



a

x

ˆi+ a

y

ˆj + a

z

ˆ

k



·



b

x

ˆi+ b

y

ˆj + b

z

ˆ

k



=

a

x

b

x

ˆi

· ˆi+ a

x

b

y

ˆi

· ˆj+ a

x

b

z

ˆi

· ˆk + a

y

b

x

ˆj

· ˆi+ a

y

b

j

ˆj

· ˆj+ · · ·

=

a

x

b

x

(1) + a

x

b

y

(0) + a

x

b

z

(0) + a

y

b

x

(0) + a

y

b

j

(1) +

· · ·

which is seen to reduce to the desired result (one might wish to show this in two dimensions before
tackling the additional tedium of working with these three-component vectors).


Document Outline


Wyszukiwarka

Podobne podstrony:
p03 062
p03 003
p03 025
p03 028
09 2005 030 033
p03 041
Fly Model 030 B17G interiors some custom parts
p03 015
10 2005 027 030
p03 023
p03 024
p03 040
2 roz 030 049
p04 030
030 2id 4629 Nieznany (2)
p03 056

więcej podobnych podstron