P16 080

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80.

(a) Hooke’s law provides the spring constant: k = (20 N)/(0.20 m) = 100 N/m.

(b) The attached mass is m = (5.0 N)/(9.8 m/s

2

) = 0.51 kg. Consequently, Eq. 16-13 leads to

T = 2π



m

k

= 2π



0.51

100

= 0.45 s .


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