p07 030

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30. Recognizing that the force in the cable must equal the total weight (since there is no acceleration), we

employ Eq. 7-47:

P = F v cos θ = mg



x

t



where we have used the fact that θ = 0

(both the force of the cable and the elevator’s motion are

upward). Thus,

P =



3.0

× 10

3

kg

 

9.8 m/s

2

 

210 m

23 s



= 2.7

× 10

5

W .


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