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\viewkind4\uc1\pard\qc\cf1\b\f0\fs24 CIP Intermediate Point\cf2\b0\fs20
\par \pard
\par \cf0\b\f1\fs22 Programming example
\par \b0\f2\fs20 N5 G90 X30 Y40 ; Circle starting point for N10
\par N10 CIP X50 Y40 I1 = 40 J1 = 45 ; End and intermediate points
\par \cf2\f0
\par \cf0\b\f1\fs22 Functionality
\par \b0\f2\fs20 If you know \b\f1 three contour points \b0\f2 of the circle, instead of center point or radius or aperture angle, then it is advantageous to use the CIP function.
\par The direction of the circle results here from the position of the intermediate point (between starting and end points). The intermediate point is written according to the axis assignment:
\par I1 =... for the X axis,
\par J1 =... for the Y axis,
\par K1 =... for the Z axis.
\par CIP remains active until cancelled by another instruction from this G group (G0, G1, G2, ...).\f3\fs16
\par }