p11 084

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84.

(a) Using Eq. 11-15 with ω = 0, we have

θ =

ω

0

+ ω

2

t = 2.8 rad .

(b) One ingredient in this calculation is α = (0

3.5 rad/s)/(1.6 s) = 2.2 rad/s

2

, so that the tangential

acceleration is = 0.33 m/s

2

. Another ingredient is ω = ω

0

+ αt = 1.3 rad/s for t = 1.0 s, so that

the radial (centripetal) acceleration is ω

2

r = 0.26 m/s

2

. Thus, the magnitude of the acceleration is

|a| =



0.33

2

+ 0.26

2

= 0.42 m/s

2

.


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