P29 066

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66.

(a) Since K = qV we have K

p

= K

d

=

1
2

K

α

(as q

α

= 2K

d

= 2K

p

).

(b) and (c) Since r =

2mK/qB

mK/q, we have

r

d

=



m

d

K

d

m

p

K

p

q

p

r

p

q

d

=



(2.00 u)K

p

(1.00 u)K

p

r

p

= 10

2 cm = 14 cm ,

r

α

=



m

α

K

α

m

p

K

p

q

p

r

p

q

α

=



(4.00 u)K

α

(1.00 u)(K

α

/2)

er

p

2e

= 10

2 cm = 14 cm .


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