53.

(a) We combine Eq. 23-28 (in absolute value) with Newton’s second law:

a =

|q|E

m

=

1.60

× 10

−19

C

9.11

× 10

−31

kg



1.40

× 10

6

N

C



= 2.46

× 10

17

m/s

2

.

(b) With v =

c

10

= 3.00

× 10

7

m/s, we use Eq. 2-11 to find

t =

v

− v

o

a

=

3.00

× 10

7

2.46

× 10

17

= 1.22

× 10

−10

s .

(c) Eq. 2-16 gives

∆x =

v

2

− v

2

o

2a

=



3.00

× 10

7



2

2 (2.46

× 10

17

)

= 1.83

× 10

−3

m .