53.
(a) We combine Eq. 23-28 (in absolute value) with Newton’s second law:
a =
|q|E
m
=
1.60
× 10
−19
C
9.11
× 10
−31
kg
1.40
× 10
6
N
C
= 2.46
× 10
17
m/s
2
.
(b) With v =
c
10
= 3.00
× 10
7
m/s, we use Eq. 2-11 to find
t =
v
− v
o
a
=
3.00
× 10
7
2.46
× 10
17
= 1.22
× 10
−10
s .
(c) Eq. 2-16 gives
∆x =
v
2
− v
2
o
2a
=
3.00
× 10
7
2
2 (2.46
× 10
17
)
= 1.83
× 10
−3
m .