p34 026

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26. The mass of the cylinder is m = ρ(πd

2

1

/4)H, where d

1

is the diameter of the cylinder. Since it is in

equilibrium

F

net

= mg

− F

r

=

πHd

2

1

4



πd

2

1

4

 

2I

c



= 0 .

We solve for H:

H

=

2I

gcρ

=



2P

πd

2

/4



1

gcρ

=

8(4.60 W)

π(2.60

× 10

3

m)

2

(9.8 m/s

2

)(3.0

× 10

8

m/s)(1.20

× 10

3

kg/m

3

)

=

4.91

× 10

7

m .


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