MAGNETYZM STAŁY |
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OBL.AUTOM. |
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OBL.MAN. |
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DEWIACJA PÓŁOKRĘŻNA |
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TYP: B1 , C1 |
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1. WYKONANIE OBSERWACJI |
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Na dewiaskopie ułożyć 2 sztaby magnetyczne A i B symulujace dewiację B1 i C1 |
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1.1 Odczytać z odpowiedniej mapy magnetycznej wartość składowej poziomej |
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magnetyzmu ziemskiego H dla podanej pozycji geograficznej |
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1.2 Zdjąć charakterystykę całkowitej dewiacji pół okrężnej |
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wywołanej magnetyzmem stałym |
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w funkcji (KM). Wykonać obserwacje co 15 stopni dla cyrkulacji w prawo a następnie w lewo |
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W PRAWO |
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W LEWO |
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KM |
KK |
d1 |
KM |
KK |
d2 |
dśrednia |
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KK |
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0 |
350 |
10 |
0 |
350 |
10 |
10 |
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350 |
+360 |
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15 |
6 |
9 |
15 |
6 |
9 |
9 |
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6 |
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30 |
21,5 |
8,5 |
30 |
21,5 |
8,5 |
8,5 |
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21,5 |
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45 |
37 |
8 |
45 |
37 |
8 |
8 |
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37 |
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60 |
53 |
7 |
60 |
53 |
7 |
7 |
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53 |
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75 |
75 |
0 |
75 |
75 |
0 |
0 |
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75 |
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90 |
97 |
-7 |
90 |
97 |
-7 |
-7 |
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97 |
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105 |
114 |
-9 |
105 |
114 |
-9 |
-9 |
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114 |
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120 |
132 |
-12 |
120 |
132 |
-12 |
-12 |
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132 |
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135 |
153 |
-18 |
135 |
153 |
-18 |
-18 |
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153 |
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150 |
163 |
-13 |
150 |
163 |
-13 |
-13 |
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163 |
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165 |
176 |
-11 |
165 |
176 |
-11 |
-11 |
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176 |
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180 |
190 |
-10 |
180 |
190 |
-10 |
-10 |
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190 |
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195 |
199 |
-4 |
195 |
199 |
-4 |
-4 |
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199 |
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210 |
211 |
-1 |
210 |
211 |
-1 |
-1 |
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211 |
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225 |
221 |
4 |
225 |
221 |
4 |
4 |
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221 |
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240 |
235 |
5 |
240 |
235 |
5 |
5 |
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235 |
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255 |
249 |
6 |
255 |
249 |
6 |
6 |
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249 |
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270 |
263 |
7 |
270 |
263 |
7 |
7 |
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263 |
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285 |
278,5 |
6,5 |
285 |
278,5 |
6,5 |
6,5 |
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278,5 |
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300 |
294 |
6 |
300 |
294 |
6 |
6 |
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294 |
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315 |
309 |
6 |
315 |
309 |
6 |
6 |
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309 |
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330 |
328 |
2 |
330 |
328 |
2 |
2 |
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328 |
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345 |
336 |
9 |
345 |
336 |
9 |
9 |
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336 |
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360 |
350 |
10 |
360 |
350 |
10 |
10 |
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350 |
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1.3 Wyznaczyć empirycznie kurs magnetyczny budowy statku |
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a |
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(poszukać KM, dla którego dewiacja jest równa zeru). |
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2. OPRACOWANIE POMIARÓW |
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1. Na podstawie danych z tabeli wykonać wykres dewiacji w funkcji kursu magnetycznego i kompasowego |
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dps= |
f(KM) |
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dps= |
f(KK) |
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2. Wyznaczyć współczynniki dewiacji B1 oraz C1 korzystając z zależności : |
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OBL.AUTOM. |
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OBL.MAN. |
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B1= |
( dE - dW )/2 |
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-7 |
[stopnie] |
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dE, dW,dN,dS |
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C1= |
( dN - dS )/2 |
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10 |
[stopnie] |
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dewiacje zaobserwowane na kursach |
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kompasowych E,W,N,S . |
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3. Obliczyć wartość siły ustawiającej igłę kompasową w kierunku północy magnetycznej na statku, |
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korzystając z zależności : |
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Hm = k1 * H |
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gdzie k1 |
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współczynnik podany przez prowadzącego |
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k1 |
= |
0,95 |
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H |
= |
17,3 |
mikroT |
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Hm |
= |
16,435 |
mikroT |
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4. Obliczyć wartość składowej wzdłużnej |
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stałego magnetyzmu okrętowego P1 oraz |
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wartość składowej poprzecznej stałego magnetyzmu okrętowego Q1 : |
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P1 = |
(B1* Hm)/57,3 |
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-2,00776614310646 |
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B1, C1 |
-w stopniach |
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Q1 = |
(C1* Hm)/57,3 |
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2,86823734729494 |
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5. Wyznaczyć analitycznie kurs budowy statku |
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a |
i porównać jego |
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wartość z wynikiem pomiaru uzyskanym uprzednio |
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-P1 |
+Q1 |
a |
NE |
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+P1 |
+Q1 |
a |
SE |
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a |
= arctg[IQ1I/IP1I] |
|
I Q1 I = |
2,86823734729494 |
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+P1 |
-Q1 |
a |
SW |
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I P1 I = |
2,00776614310646 |
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-P1 |
-Q1 |
a |
NW |
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Kurs Magnetyczny Budowy Statku (s.ćwiartkowy) |
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a |
55,0079798014413 |
a |
55,0079798014413 |
system pełny |
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7.Obliczyć wartość składowej poziomej stałego magnetyzmu okrętowego M1 : |
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M1 = |
(P12 + Q12)1/2 |
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3,50112986988802 |
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8. Przedstawić na jednym wykresie (dla KK co 15 stopni) |
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dpsB1= |
B1* sin(KK) |
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dewiacja półokrężna typu B1 |
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dpsC1= |
C1* cos(KK) |
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dewiacja półokrężna typu C1 |
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9. Obliczyć wartości sil ustawiających Hk1, Hk2, Hk |
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gdzie Hk1, Hk2, Hk : |
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Obliczenia wykonać dla KK od 000 do 345 w odstępach co 15 stopni |
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Hk1 - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i P1) |
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Hk2 - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i Q1) |
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Hk - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i M1) |
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9.1 |
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Hk1 = |
[P1*sin(KK + dps(B1))]/[sin(dps(B1))] |
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dla KK = 000 |
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Hk1 = Hm+ P1 |
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14,4272338568935 |
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dla KK = 180 |
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Hk1 = HM - P1 |
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18,4427661431065 |
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9.2 |
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Hk2 = |
[Q1*cos(KK + dps(C1))]/[sin(dps(C1))] |
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dla KK = 090 |
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Hk2 = Hm - Q1 |
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13,5667626527051 |
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dla KK = 270 |
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Hk2 = HM + Q1 |
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19,3032373472949 |
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9.3 |
|
Hk = |
[M1*sin(KK + dps + a)]/[sin(dps)] |
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dla dps = 0 |
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Hk = Hm + M1 |
|
19,936129869888 |
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|
jeżeli zwroty wektórow Hm i M1 są zgodne |
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dla dps = 0 |
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Hk = Hm - M1 |
|
12,933870130112 |
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|
jeżeli zwroty wektórow Hm i M1 są przeciwne |
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Hk = |
[M1*sin(KK + dps + a)]/[sin(dps)] |
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+P , +Q |
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Hk = |
[M1*sin(KK + dps - a)]/[sin(dps)] |
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+P , -Q |
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Hk = |
[M1*sin((KK+ dps - a)]/[sin(dps)] |
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-P , +Q |
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Hk = |
[M1*sin((KK + dps + a)]/[sin(dps)] |
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-P , -Q |
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0,00000 |
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UWAGA NA |
|
a |
|
TRZEBA PRZEKSZTAŁCAĆ WZÓR 9.3 |
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AQ |
AR |
AS |
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Zestaw Obliczeń pkt 8 i pkt 9 |
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system ćwiartkowy |
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????SPRAWDZIĆ |
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TAN=Y/X |
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KK |
ALFA |
DEW |
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A |
A |
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KK |
P1 |
Q1 |
M1 |
a |
dpsB1 |
dpsC1 |
dps |
Hk1 |
Hk2 |
Hk |
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|
WZOR COSINUSÓW |
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Hm |
Nm Hm |
Nm Hm |
X |
Y |
|
M |
Nm M |
|
Nm M |
X |
Y |
|
SUMA |
SUMA |
Hk |
|
Hk |
HK |
|
ATAN(Y/X) |
ATAN(Y/X) |
|
KK |
ALFA |
DEW |
|
|
|
|
|
|
|
|
|
KONTROLA |
|
|
|
|
|
|
|
|
14,1775565192348 |
3,501 |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
KĄT X |
RADIANY |
|
|
|
RAD |
|
|
|
|
deg |
rad |
|
|
|
|
deg |
|
rad |
|
|
|
X |
Y |
X2+Y2 |
|
X/COS A |
Y/SIN A |
|
RAD |
DEG |
|
|
|
|
|
DEG |
|
|
|
|
DEG |
|
DEG |
RAD |
SIN |
LICZNIK |
|
MIANOWNIK |
|
Hk |
|
|
MIAN |
SIN(A) |
|
|
|
KK-D-A |
MOD |
Bt/180 |
|
|
|
|
0 |
-2,008 |
2,868 |
3,501 |
55,0 |
0,0 |
10,0 |
10,0 |
14,43 |
16,27 |
14,26 |
- H170 |
45,00798 |
0,78554 |
14,2 |
14,2 |
201,003108856098 |
0,78554 |
|
45,01 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,4 |
135,0 |
2,35605521638354 |
-2,47532785244065 |
2,47601744516343 |
|
13,960 |
2,476 |
14,178 |
|
14,178 |
14,178 |
18,2743484651688 |
0,176 |
10,058 |
|
0 |
55,0 |
10,0 |
|
-65,0 |
65,0 |
|
|
|
65,0 |
65,0079798014413 |
115,0 |
1,13460 |
0,90637 |
3,17331 |
0,17453 |
0,17365 |
|
18,27 |
|
|
2,46190685333503 |
0,7031749591779 |
44,6822897201094 |
|
|
-65,0 |
65,0079798014413 |
0,361155443341341 |
0,00 |
|
|
|
15 |
-2,008 |
2,868 |
3,501 |
55,0 |
-1,8 |
9,7 |
7,8 |
14,49 |
15,54 |
13,65 |
|
32,16045 |
0,56131 |
13,6 |
13,6 |
184,943113379226 |
0,56131 |
|
32,16 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,4 |
147,8 |
2,58028682744382 |
-2,96391913558249 |
1,8636238149235 |
|
13,471 |
1,864 |
13,599 |
|
13,599 |
13,599 |
19,0126053768535 |
0,137 |
7,876 |
|
15 |
55,0 |
7,8 |
|
-47,9 |
47,9 |
|
|
|
77,9 |
77,8555047486144 |
102,1 |
1,35883 |
0,97762 |
3,42278 |
0,13697 |
0,13654 |
|
25,07 |
|
|
1,85682275751934 |
0,530349580428085 |
32,0290776112498 |
|
|
-47,9 |
47,8555047486144 |
0,26586391527008 |
0,00 |
|
|
|
30 |
-2,008 |
2,868 |
3,501 |
55,0 |
-3,5 |
8,7 |
5,2 |
14,67 |
14,87 |
13,22 |
|
19,84773 |
0,34641 |
13,2 |
13,2 |
174,121073130644 |
0,34641 |
|
19,85 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,4 |
160,2 |
2,79518448998212 |
-3,29315674582228 |
1,1887089691204 |
|
13,142 |
1,189 |
13,195 |
|
13,195 |
13,195 |
19,5622267853633 |
0,090 |
5,168 |
|
30 |
55,0 |
5,2 |
|
-30,2 |
30,2 |
|
|
|
90,2 |
90,1682338392857 |
89,8 |
1,57373 |
1,00000 |
3,50111 |
0,09006 |
0,08994 |
|
38,93 |
|
|
1,18682540583773 |
0,338983542440169 |
19,8149580872988 |
|
|
-30,2 |
30,1682338392857 |
0,167601299107143 |
0,00 |
|
|
|
45 |
-2,008 |
2,868 |
3,501 |
55,0 |
-4,9 |
7,1 |
2,1 |
14,97 |
14,32 |
12,98 |
|
7,88666 |
0,13765 |
13,0 |
13,0 |
168,373508032518 |
0,13765 |
|
7,89 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,5 |
172,1 |
3,00394447906621 |
-3,4680142176241 |
0,480403738723189 |
|
12,967 |
0,480 |
12,976 |
|
12,976 |
12,976 |
19,8741348832124 |
0,037 |
2,122 |
|
45 |
55,0 |
2,1 |
|
-12,1 |
12,1 |
|
|
|
102,1 |
102,129300145001 |
77,9 |
1,78249 |
0,97768 |
3,42297 |
0,03702 |
0,03702 |
|
92,47 |
|
|
0,480309614265922 |
0,137187031648525 |
7,88510441119652 |
|
|
-12,1 |
12,129300145001 |
0,067385000805561 |
0,00 |
|
|
|
60 |
-2,008 |
2,868 |
3,501 |
55,0 |
-6,1 |
5,0 |
-1,1 |
15,37 |
13,91 |
12,94 |
|
3,92984 |
0,06859 |
12,9 |
12,9 |
167,555587114965 |
0,06859 |
|
3,93 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,5 |
183,9 |
3,21018134206676 |
-3,49289772591593 |
-0,23994966579139 |
|
12,942 |
-0,240 |
12,944 |
|
12,944 |
12,944 |
19,9197562664622 |
-0,019 |
-1,062 |
|
60 |
55,0 |
-1,1 |
|
6,1 |
6,1 |
|
|
|
113,9 |
113,94580197495 |
66,1 |
1,98873 |
0,91393 |
3,19979 |
-0,01854 |
0,01854 |
|
172,61 |
|
|
0,239954654871098 |
0,068536347918672 |
3,92992421048582 |
|
|
6,1 |
6,05419802504973 |
0,033634433472499 |
0,00 |
|
|
|
75 |
-2,008 |
2,868 |
3,501 |
55,0 |
-6,8 |
2,6 |
-4,2 |
15,84 |
13,65 |
13,11 |
|
15,81873 |
0,27609 |
13,1 |
13,1 |
171,643279783029 |
0,27609 |
|
15,82 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,5 |
195,8 |
3,41768157322738 |
-3,36853835055653 |
-0,95438972472047 |
|
13,066 |
-0,954 |
13,101 |
|
13,101 |
13,101 |
19,6948696316204 |
-0,073 |
-4,178 |
|
75 |
55,0 |
-4,2 |
|
24,2 |
24,2 |
|
|
|
125,8 |
125,834689468443 |
54,2 |
2,19623 |
0,81071 |
2,83840 |
-0,07284 |
0,07277 |
|
39,00 |
|
|
0,953422263688418 |
0,272318451220124 |
15,8022749008644 |
|
|
24,2 |
24,1653105315569 |
0,134251725175316 |
0,00 |
|
|
|
90 |
-2,008 |
2,868 |
3,501 |
55,0 |
-7,0 |
0,0 |
-7,0 |
16,35 |
13,57 |
13,48 |
- H181 |
27,99202 |
0,48855 |
13,4 |
13,4 |
180,748114240005 |
0,48855 |
|
27,99 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,6 |
208,0 |
3,6301455703394 |
-3,09154308262298 |
-1,6432503564911 |
|
13,343 |
-1,643 |
13,444 |
|
13,444 |
13,444 |
19,2201803631123 |
-0,123 |
-7,021 |
|
90 |
55,0 |
-7,0 |
|
42,0 |
42,0 |
|
|
|
138,0 |
138,007979801441 |
42,0 |
2,40869 |
0,66903 |
2,34235 |
-0,12217 |
0,12187 |
|
19,22 |
|
|
1,63844308117227 |
0,467975522777358 |
27,9029633885627 |
|
|
42,0 |
41,9920201985587 |
0,233289001103104 |
0,00 |
|
|
|
105 |
-2,008 |
2,868 |
3,501 |
55,0 |
-6,8 |
-2,6 |
-9,3 |
16,88 |
13,65 |
14,04 |
|
40,64235 |
0,70934 |
14,0 |
14,0 |
195,043948432522 |
0,70934 |
|
40,64 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,6 |
220,6 |
3,85093545874755 |
-2,65662266301492 |
-2,28040925979913 |
|
13,778 |
-2,280 |
13,966 |
|
13,966 |
13,966 |
18,538516973594 |
-0,164 |
-9,398 |
|
105 |
55,0 |
-9,3 |
|
59,3 |
59,3 |
|
|
|
150,7 |
150,658308566393 |
29,3 |
2,62948 |
0,49002 |
1,71561 |
-0,16318 |
0,16246 |
|
10,56 |
|
|
2,26887617968804 |
0,648041136434797 |
40,394074254522 |
|
|
59,3 |
59,3416914336073 |
0,329676063520041 |
0,00 |
|
|
|
120 |
-2,008 |
2,868 |
3,501 |
55,0 |
-6,1 |
-5,0 |
-11,1 |
17,38 |
13,91 |
14,75 |
|
53,92984 |
0,94125 |
14,6 |
14,6 |
214,609598694745 |
0,94125 |
|
53,93 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,6 |
233,9 |
4,08284596806392 |
-2,0613792720133 |
-2,82995156543995 |
|
14,374 |
-2,830 |
14,650 |
|
14,650 |
14,650 |
17,7091650728105 |
-0,194 |
-11,138 |
|
120 |
55,0 |
-11,1 |
|
76,1 |
76,1 |
|
|
|
163,9 |
163,94580197495 |
16,1 |
2,86139 |
0,27655 |
0,96823 |
-0,19307 |
0,19187 |
|
5,05 |
|
|
2,81087184410059 |
0,802847066107402 |
53,4028437110588 |
|
|
76,1 |
76,0541980250497 |
0,422523322361387 |
0,00 |
|
|
|
135 |
-2,008 |
2,868 |
3,501 |
55,0 |
-4,9 |
-7,1 |
-12,0 |
17,81 |
14,32 |
15,58 |
|
67,97120 |
1,18632 |
15,5 |
15,5 |
239,20298755795 |
1,18632 |
|
67,97 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,7 |
248,0 |
4,32791397596342 |
-1,3131776029167 |
-3,2455315356687 |
|
15,122 |
-3,246 |
15,466 |
|
15,466 |
15,466 |
16,8004007102479 |
-0,211 |
-12,113 |
|
135 |
55,0 |
-12,0 |
|
92,0 |
92,0 |
|
|
|
178,0 |
177,98716452127 |
2,0 |
3,10646 |
0,03512 |
0,12297 |
-0,20980 |
0,20827 |
|
0,59 |
|
|
3,22109720243537 |
0,9200164867173 |
66,9284922985247 |
|
|
92,0 |
92,01283547873 |
0,511182419326278 |
0,00 |
|
|
|
150 |
-2,008 |
2,868 |
3,501 |
55,0 |
-3,5 |
-8,7 |
-12,2 |
18,15 |
14,87 |
16,49 |
|
82,83177 |
1,44569 |
16,4 |
16,4 |
268,00682218982 |
1,44569 |
|
82,83 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,7 |
262,8 |
4,58727969833628 |
-0,436882055856475 |
-3,47376516694677 |
|
15,998 |
-3,474 |
16,371 |
|
16,371 |
16,371 |
15,881637860617 |
-0,214 |
-12,251 |
|
150 |
55,0 |
-12,2 |
|
107,2 |
107,2 |
|
|
|
192,8 |
12,8477257635969 |
-12,8 |
0,22424 |
0,22236 |
0,77851 |
-0,21224 |
0,21065 |
|
3,70 |
|
|
3,44847922495051 |
0,984961813216259 |
80,0509612017993 |
|
|
107,2 |
107,152274236403 |
0,595290412424461 |
0,00 |
|
|
|
165 |
-2,008 |
2,868 |
3,501 |
55,0 |
-1,8 |
-9,7 |
-11,5 |
18,37 |
15,54 |
17,41 |
|
98,52103 |
1,71952 |
17,3 |
17,3 |
299,419130741872 |
1,71952 |
|
98,52 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,8 |
278,5 |
4,86110898545949 |
0,518770775054769 |
-3,46248281566438 |
|
16,954 |
-3,462 |
17,304 |
|
17,304 |
17,304 |
15,0166317053444 |
-0,201 |
-11,543 |
|
165 |
55,0 |
-11,5 |
|
121,5 |
121,5 |
|
|
|
208,5 |
28,536988222833 |
-28,5 |
0,49806 |
0,47773 |
1,67258 |
-0,20021 |
0,19887 |
|
8,41 |
|
|
3,44122393059823 |
0,982889540943619 |
79,3857414855162 |
|
|
121,5 |
121,463011777167 |
0,67479450987315 |
0,00 |
|
|
|
180 |
-2,008 |
2,868 |
3,501 |
55,0 |
0,0 |
-10,0 |
-10,0 |
18,44 |
16,27 |
18,27 |
- H172 |
114,99202 |
2,00699 |
18,2 |
18,2 |
330,988422125266 |
2,00699 |
|
114,99 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,8 |
295,0 |
5,14858201957447 |
1,47919947549266 |
-3,17330730902702 |
|
17,914 |
-3,173 |
18,193 |
|
18,193 |
18,193 |
14,2588161789559 |
-0,175 |
-10,045 |
|
180 |
55,0 |
-10,0 |
|
135,0 |
135,0 |
|
|
|
225,0 |
45,0079798014413 |
-45,0 |
0,78554 |
0,70721 |
2,47602 |
-0,17453 |
0,17365 |
|
14,26 |
|
|
3,15919643964903 |
0,902336262022202 |
64,466878233088 |
|
|
135,0 |
134,992020198559 |
0,74995566776977 |
0,00 |
|
|
|
195 |
-2,008 |
2,868 |
3,501 |
55,0 |
1,8 |
-9,7 |
-7,8 |
18,37 |
17,02 |
19,01 |
|
132,14450 |
2,30636 |
19,0 |
19,0 |
359,587552807639 |
2,30636 |
|
132,14 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,9 |
312,1 |
5,44794918411248 |
2,34926733927035 |
-2,59593014822427 |
|
18,784 |
-2,596 |
18,963 |
|
18,963 |
18,963 |
13,6491901325943 |
-0,137 |
-7,868 |
|
195 |
55,0 |
-7,8 |
|
147,8 |
147,8 |
|
|
|
242,2 |
62,1604548542683 |
-62,2 |
1,08490 |
0,88426 |
3,09591 |
-0,13697 |
0,13654 |
|
22,67 |
|
|
2,58912902389374 |
0,739512420308064 |
47,6898978117831 |
|
|
147,8 |
147,839545145732 |
0,821330806365176 |
0,00 |
|
|
|
210 |
-2,008 |
2,868 |
3,501 |
55,0 |
3,5 |
-8,7 |
-5,2 |
18,15 |
17,74 |
19,56 |
|
149,83177 |
2,61506 |
19,5 |
19,5 |
381,861807658274 |
2,61506 |
|
149,83 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
0,9 |
329,8 |
5,75665029717248 |
3,02691427722701 |
-1,75946023659001 |
|
19,462 |
-1,759 |
19,541 |
|
19,541 |
19,541 |
13,2164364684914 |
-0,090 |
-5,166 |
|
210 |
55,0 |
-5,2 |
|
160,2 |
160,2 |
|
|
|
259,8 |
79,847725763597 |
-79,8 |
1,39361 |
0,98434 |
3,44631 |
-0,09006 |
0,08994 |
|
38,32 |
|
|
1,75757666934883 |
0,502002706173547 |
30,1325866621487 |
|
|
160,2 |
160,152274236403 |
0,889734856868906 |
0,00 |
|
|
|
225 |
-2,008 |
2,868 |
3,501 |
55,0 |
4,9 |
-7,1 |
-2,1 |
17,81 |
18,38 |
19,87 |
|
167,87070 |
2,92990 |
19,9 |
19,9 |
394,88017054801 |
2,92990 |
|
167,87 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
1,0 |
347,9 |
6,07148908368669 |
3,42297034323662 |
-0,735652360252235 |
|
19,858 |
-0,736 |
19,872 |
|
19,872 |
19,872 |
12,9784246169081 |
-0,037 |
-2,122 |
|
225 |
55,0 |
-2,1 |
|
172,1 |
172,1 |
|
|
|
277,9 |
97,8866594578817 |
-97,9 |
1,70844 |
0,99054 |
3,46801 |
-0,03702 |
0,03702 |
|
93,69 |
|
|
0,735558235790575 |
0,210091674152636 |
12,127724636619 |
|
|
172,1 |
172,113340542118 |
0,956185225233991 |
0,00 |
|
|
|
240 |
-2,008 |
2,868 |
3,501 |
55,0 |
6,1 |
-5,0 |
1,1 |
17,38 |
18,88 |
19,92 |
|
186,05420 |
3,24726 |
19,9 |
19,9 |
396,807412008229 |
3,24726 |
|
186,05 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
1,0 |
6,1 |
0,105665689104855 |
3,48160257506561 |
0,369261255913256 |
|
19,917 |
0,369 |
19,920 |
|
19,920 |
19,920 |
12,9440573096745 |
0,019 |
1,062 |
|
240 |
55,0 |
1,1 |
|
183,9 |
183,9 |
|
|
|
296,1 |
116,070157627932 |
-116,1 |
2,02581 |
0,89826 |
3,14491 |
0,01854 |
0,01854 |
|
169,65 |
|
|
0,36926624499296 |
0,105470593412969 |
6,05428012897343 |
|
|
183,9 |
183,929842372068 |
1,0218324576226 |
1,00 |
|
|
|
255 |
-2,008 |
2,868 |
3,501 |
55,0 |
6,8 |
-2,6 |
4,2 |
16,88 |
19,19 |
19,69 |
|
204,16531 |
3,56336 |
19,7 |
19,7 |
387,364411737323 |
3,56336 |
|
204,17 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
1,1 |
24,2 |
0,421764233542529 |
3,19431932982966 |
1,43326005487443 |
|
19,629 |
1,433 |
19,682 |
|
19,682 |
19,682 |
13,1145643403663 |
0,073 |
4,176 |
|
255 |
55,0 |
4,2 |
|
195,8 |
195,8 |
|
|
|
314,2 |
134,18127013444 |
-134,2 |
2,34190 |
0,71714 |
2,51079 |
0,07284 |
0,07277 |
|
34,50 |
|
|
1,43229259296862 |
0,409094391295583 |
24,1479585660023 |
|
|
195,8 |
195,81872986556 |
1,08788183258645 |
1,00 |
|
|
|
270 |
-2,008 |
2,868 |
3,501 |
55,0 |
7,0 |
0,0 |
7,0 |
16,35 |
19,30 |
19,22 |
- H183 |
221,99202 |
3,87449 |
19,2 |
19,2 |
367,900555284731 |
3,87449 |
|
221,99 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
1,1 |
42,0 |
0,732899012028811 |
2,60217279948004 |
2,34235076098101 |
|
19,037 |
2,342 |
19,181 |
|
19,181 |
19,181 |
13,4837056685225 |
0,122 |
7,014 |
|
270 |
55,0 |
7,0 |
|
208,0 |
208,0 |
|
|
|
332,0 |
152,007979801441 |
-152,0 |
2,65304 |
0,46935 |
1,64325 |
0,12217 |
0,12187 |
|
13,48 |
|
|
2,33754345386247 |
0,667654026195044 |
41,8862586121101 |
|
|
208,0 |
207,992020198559 |
1,15551122332533 |
1,00 |
|
|
|
285 |
-2,008 |
2,868 |
3,501 |
55,0 |
6,8 |
2,6 |
9,3 |
15,84 |
19,19 |
18,54 |
|
239,34169 |
4,17730 |
18,5 |
18,5 |
341,049486881139 |
4,17730 |
|
239,34 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
1,2 |
59,3 |
1,03570789921896 |
1,78528602115354 |
3,01175433734159 |
|
18,220 |
3,012 |
18,468 |
|
18,468 |
18,468 |
14,0368041461319 |
0,164 |
9,386 |
|
285 |
55,0 |
9,3 |
|
220,6 |
220,6 |
|
|
|
349,4 |
169,35765103649 |
-169,4 |
2,95585 |
0,18468 |
0,64658 |
0,16318 |
0,16246 |
|
3,98 |
|
|
3,00022106350612 |
0,856929384228208 |
58,973542976653 |
|
|
220,6 |
220,64234896351 |
1,22579082757506 |
1,00 |
|
|
|
300 |
-2,008 |
2,868 |
3,501 |
55,0 |
6,1 |
5,0 |
11,1 |
15,37 |
18,88 |
17,71 |
|
256,05420 |
4,46899 |
17,6 |
17,6 |
310,102385603653 |
4,46899 |
|
256,05 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
1,2 |
76,1 |
1,32739616550089 |
0,843786134403129 |
3,39793103597043 |
|
17,279 |
3,398 |
17,610 |
|
17,610 |
17,610 |
14,7489984022355 |
0,194 |
11,125 |
|
300 |
55,0 |
11,1 |
|
233,9 |
233,9 |
|
|
|
366,1 |
6,07015762793242 |
-186,1 |
0,10594 |
0,10575 |
0,37023 |
0,19307 |
0,19187 |
|
1,93 |
|
|
3,3788508984589 |
0,965074425693033 |
74,8126647684268 |
|
|
233,9 |
233,929842372068 |
1,29961023540038 |
1,00 |
|
|
|
315 |
-2,008 |
2,868 |
3,501 |
55,0 |
4,9 |
7,1 |
12,0 |
14,97 |
18,38 |
16,80 |
|
272,01284 |
4,74752 |
16,7 |
16,7 |
278,325061589627 |
4,74752 |
|
272,01 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
1,3 |
92,0 |
1,60592693319969 |
-0,122971517377409 |
3,4989696157206 |
|
16,312 |
3,499 |
16,683 |
|
16,683 |
16,683 |
15,583510663253 |
0,211 |
12,107 |
|
315 |
55,0 |
12,0 |
|
248,0 |
248,0 |
|
|
|
382,0 |
22,0287950816127 |
-202,0 |
0,38448 |
0,37507 |
1,31318 |
0,20980 |
0,20827 |
|
6,31 |
|
|
3,47453497587367 |
0,992403911022244 |
82,9334416860961 |
|
|
248,0 |
247,971204918387 |
1,37761780510215 |
1,00 |
|
|
|
330 |
-2,008 |
2,868 |
3,501 |
55,0 |
3,5 |
8,7 |
12,2 |
14,67 |
17,74 |
15,88 |
|
287,15227 |
5,01175 |
15,8 |
15,8 |
248,428005437531 |
5,01175 |
|
287,15 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
1,3 |
107,2 |
1,87015998642513 |
-1,0325260093791 |
3,3454148331377 |
|
15,402 |
3,345 |
15,762 |
|
15,762 |
15,762 |
16,4909534828991 |
0,214 |
12,254 |
|
330 |
55,0 |
12,2 |
|
262,8 |
262,8 |
|
|
|
397,2 |
37,1682338392857 |
-217,2 |
0,64871 |
0,60416 |
2,11523 |
0,21224 |
0,21065 |
|
10,04 |
|
|
3,32012905760202 |
0,94830217129541 |
71,4961210373914 |
|
|
262,8 |
262,831766160714 |
1,46017647867063 |
1,00 |
|
|
|
345 |
-2,008 |
2,868 |
3,501 |
55,0 |
1,8 |
9,7 |
11,5 |
14,49 |
17,02 |
15,02 |
|
301,46301 |
5,26152 |
14,9 |
14,9 |
222,300240853106 |
5,26152 |
|
301,46 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
1,3 |
121,5 |
2,11992947490021 |
-1,82740780385509 |
2,98638428274588 |
|
14,608 |
2,986 |
14,910 |
|
14,910 |
14,910 |
17,4106291441865 |
0,202 |
11,554 |
|
345 |
55,0 |
11,5 |
|
278,5 |
278,5 |
|
|
|
411,5 |
51,4789713800497 |
-231,5 |
0,89848 |
0,78238 |
2,73921 |
0,20021 |
0,19887 |
|
13,77 |
|
|
2,9651258319639 |
0,846905411154811 |
57,876663286132 |
|
|
278,5 |
278,52102861995 |
1,54733904788861 |
1,00 |
|
|
|
360 |
-2,008 |
2,868 |
3,501 |
55,0 |
0,0 |
10,0 |
10,0 |
14,43 |
16,27 |
14,26 |
|
314,99202 |
5,49765 |
14,2 |
14,2 |
201,003108856098 |
5,49765 |
|
314,99 |
|
16,435 |
0 |
0 |
16,435 |
0 |
|
3,501 |
1,4 |
135,0 |
2,35605521638354 |
-2,47532785244065 |
2,47601744516343 |
|
13,960 |
2,476 |
14,178 |
|
14,178 |
14,178 |
18,2743484651688 |
0,176 |
10,058 |
|
360 |
55,0 |
10,0 |
|
295,0 |
295,0 |
|
|
|
425,0 |
65,0079798014414 |
-245,0 |
1,13460 |
0,90637 |
3,17331 |
0,17453 |
0,17365 |
|
18,27 |
|
|
2,46190685333504 |
0,703174959177901 |
44,6822897201094 |
|
|
295,0 |
294,992020198559 |
1,63884455665866 |
1,00 |
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10. Wykresy dewiacji i sił ustawiajacych |
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11. Dyskusja wyników i wnioski . |
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MAGNETYZM OKRĘTOWY ZMIENNY |
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OBL.AUTOM. |
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OBL.MAN. |
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DEW PÓŁOKRĘŻNA |
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TYP : B2 C2 |
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1. WYKONANIE OBSERWACJI |
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Na dewiaskopie ułożyć sztaby stali miekkiej c i f |
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1.1 Odczytać z odpowiedniej mapy magnetycznej wartość składowej poziomej i pionowej |
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magnetyzmu ziemskiego H i Z dla podanej pozycji geograficznej |
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1.2 Zdjąć charakterystykę całkowitej dewiacji półokrężnej |
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wywołanej magnetyzmem zmiennym |
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zmiennym magnetyzmem okrętowym |
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w funkcji (KM). Wykonać obserwacje co 15 stopni dla cyrkulacji w prawo a następnie w lewo |
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W PRAWO |
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W LEWO |
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średnia |
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KM |
KK |
d1 |
KM |
KK |
d2 |
dpz |
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KK |
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0 |
9 |
-9 |
0 |
11 |
-11 |
-10 |
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10 |
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15 |
23 |
-8 |
15 |
25 |
-10 |
-9 |
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24 |
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30 |
37 |
-7 |
30 |
39 |
-9 |
-8 |
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38 |
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45 |
51 |
-6 |
45 |
53 |
-8 |
-7 |
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52 |
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60 |
65 |
-5 |
60 |
67 |
-7 |
-6 |
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66 |
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75 |
79 |
-4 |
75 |
81 |
-6 |
-5 |
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80 |
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90 |
93 |
-3 |
90 |
95 |
-5 |
-4 |
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94 |
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105 |
107 |
-2 |
105 |
109 |
-4 |
-3 |
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108 |
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120 |
121 |
-1 |
120 |
123 |
-3 |
-2 |
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122 |
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135 |
135 |
0 |
135 |
137 |
-2 |
-1 |
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136 |
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150 |
149 |
1 |
150 |
151 |
-1 |
0 |
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150 |
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165 |
163 |
2 |
165 |
165 |
0 |
1 |
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164 |
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180 |
177 |
3 |
180 |
179 |
1 |
2 |
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178 |
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195 |
191 |
4 |
195 |
193 |
2 |
3 |
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192 |
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210 |
205 |
5 |
210 |
207 |
3 |
4 |
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206 |
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225 |
219 |
6 |
225 |
221 |
4 |
5 |
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220 |
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240 |
235 |
5 |
240 |
235 |
5 |
5 |
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235 |
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255 |
251 |
4 |
255 |
249 |
6 |
5 |
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250 |
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270 |
268 |
2 |
270 |
265 |
5 |
3,5 |
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266,5 |
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285 |
283 |
2 |
285 |
281 |
4 |
3 |
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282 |
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300 |
299 |
1 |
300 |
297 |
3 |
2 |
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298 |
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315 |
315 |
0 |
315 |
313 |
2 |
1 |
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314 |
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330 |
331 |
-1 |
330 |
329 |
1 |
0 |
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330 |
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345 |
347 |
-2 |
345 |
345 |
0 |
-1 |
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346 |
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360 |
363 |
-3 |
360 |
361 |
-1 |
-2 |
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362 |
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2. OPRACOWANIE POMIARÓW |
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1. Na podstawie danych z tabeli wykonać wykres dewiacji w funkcji kursu magnetycznego i kompasowego |
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dpz= |
f(KM) |
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dpz= |
f(KK) |
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2. Wyznaczyć współczynniki dewiacji B2 oraz C2 korzystając z zależności : |
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OBL.AUTOM. |
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OBL.MAN. |
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B2= |
( dE - dW )/2 |
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-0,25 |
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dE, dW,dN,dS |
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C2= |
( dN - dS )/2 |
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-4 |
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dewiacje zaobserwowane na kursach |
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kompasowych E,W,N,S . |
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3. Obliczyć wartość siły ustawiającej igłę kompasową w kierunku północy magnetycznej na statku, |
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korzystając z zależności : |
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Hm = k1 * H |
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gdzie k1 |
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współczynnik podany przez prowadzącego |
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k1 |
= |
0,95 |
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H |
= |
18 |
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Hm |
= |
17,1 |
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Z |
= |
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40 |
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4. Obliczyć wartość składowej wzdłużnej |
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stałego magnetyzmu okrętowego P2 oraz |
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wartość składowej poprzecznej stałego magnetyzmu okrętowego Q2 : |
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P2 = |
(B2* Hm)/57,3 |
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-0,074607329842932 |
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B2, C2 |
-w stopniach |
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Q2 = |
(C2* Hm)/57,3 |
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-1,19371727748691 |
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5. Kąt |
a1 |
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a1 = |
kąt pomiędzy wektorem P2 a wektorem M2 |
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UWAGA- DANE P1 i Q1 mogą mieć odmienne znaki niż P2 i Q2 |
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-P2 |
+Q2 |
a |
NE |
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+P2 |
+Q2 |
a |
SE |
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a1 |
= arctg[IQ2I/IP2I] |
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ABS Q2= |
1,19371727748691 |
Q2 = |
-0,074607 |
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+P2 |
-Q2 |
a |
SW |
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ABS P2= |
0,074607329842932 |
P2 = |
-1,193717 |
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-P2 |
-Q2 |
a |
NW |
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a1 |
86,4236656250027 |
a1 |
266,423665625003 |
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a1 = |
artg[ I Q2 I / I P2 I ] |
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quadrantal |
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full |
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7.Obliczyć wartość składowej poziomej zmiennego magnetyzmu okrętowego M2 : |
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M2 = |
(P22 + Q22)1/2 |
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1,1960464841456 |
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8. Wyznaczyć wartości parametrów c , f sztab pionowych c i f ; |
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c = |
P2/Z |
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-0,001865183246073 |
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f = |
Q2/Z |
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-0,029842931937173 |
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8. Przedstawić na jednym wykresie (dla KK co 15 stopni) |
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dpzB2= |
B2* sin(KK) |
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dewiacja półokrężna typu B2 |
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dpzC2= |
C2* cos(KK) |
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dewiacja półokrężna typu C2 |
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dpz = |
B2* sin(KK) + C2* cos(KK) |
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całkowita dewiacja półokrężna wywołana zmiennym polem magnetycznym okrętu |
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9. Obliczyć wartości sil ustawiających Hk1, Hk2, Hk |
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gdzie Hk1, Hk2, Hk : |
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Obliczenia wykonać dla KK od 000 do 345 w odstępach co 15 stopni |
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Hk1 - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i P2) |
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Hk2 - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i Q2) |
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Hk - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i M2) |
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9.1 |
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Hk1 = |
[P2*sin(KK + dpz(B2))]/[sin(dpz(B2))] |
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dla KK = 000 |
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Hk1 = Hm+ P2 |
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17,0253926701571 |
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dla KK = 180 |
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Hk1 = HM - P2 |
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17,1746073298429 |
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9.2 |
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Hk2 = |
[Q2*cos(KK + dpz(C2))]/[sin(dpz(C2))] |
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dla KK = 090 |
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Hk2 = Hm - Q2 |
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18,2937172774869 |
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dla KK = 270 |
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Hk2 = HM + Q2 |
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15,9062827225131 |
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9.3 |
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a1 = |
artg[ I Q2 I / I P2 I ] |
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Hk = |
[M2*sin(KK + dpz + a)]/[sin(dpz)] |
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dla dpz = 0 |
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Hk = Hm + M2 |
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18,2960464841456 |
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jeżeli zwroty wektórow Hm i M2 są zgodne |
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Hk = |
[M2*sin(KK + dps + a)]/[sin(dps)] |
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+P , +Q |
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dla dpz = 0 |
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Hk = Hm - M2 |
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15,9039535158544 |
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jeżeli zwroty wektórow Hm i M2 są przeciwne |
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Hk = |
[M2*sin(KK + dps - a)]/[sin(dps)] |
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+P , -Q |
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Hk = |
[M2*sin((KK+ dps - a)]/[sin(dps)] |
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-P , +Q |
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Hk = |
[M2*sin((KK + dps + a)]/[sin(dps)] |
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-P , -Q |
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Zestaw Obliczeń pkt 8 i pkt 9 |
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KK |
P2 |
Q2 |
M2 |
a1 |
dpzB2 |
dpzC2 |
dpz |
Hk1 |
Hk2 |
Hk |
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0 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,0 |
-4,0 |
-4,0 |
17,0253926701571 |
17,07 |
17,00 |
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15 |
-0,075 |
-1,194 |
1,196 |
86,4 |
-0,1 |
-3,9 |
-3,9 |
17,03 |
17,38 |
17,31 |
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30 |
-0,075 |
-1,194 |
1,196 |
86,4 |
-0,1 |
-3,5 |
-3,6 |
17,03 |
17,67 |
17,61 |
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45 |
-0,075 |
-1,194 |
1,196 |
86,4 |
-0,2 |
-2,8 |
-3,0 |
17,05 |
17,93 |
17,87 |
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60 |
-0,075 |
-1,194 |
1,196 |
86,4 |
-0,2 |
-2,0 |
-2,2 |
17,06 |
18,13 |
18,09 |
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75 |
-0,075 |
-1,194 |
1,196 |
86,4 |
-0,2 |
-1,0 |
-1,3 |
17,08 |
18,25 |
18,23 |
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90 |
-0,075 |
-1,194 |
1,196 |
86,4 |
-0,3 |
0,0 |
-0,3 |
17,10 |
18,29 |
18,29 |
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105 |
-0,075 |
-1,194 |
1,196 |
86,4 |
-0,2 |
1,0 |
0,8 |
17,12 |
18,25 |
18,27 |
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120 |
-0,075 |
-1,194 |
1,196 |
86,4 |
-0,2 |
2,0 |
1,8 |
17,14 |
18,13 |
18,16 |
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135 |
-0,075 |
-1,194 |
1,196 |
86,4 |
-0,2 |
2,8 |
2,7 |
17,15 |
17,93 |
17,98 |
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150 |
-0,075 |
-1,194 |
1,196 |
86,4 |
-0,1 |
3,5 |
3,3 |
17,16 |
17,67 |
17,74 |
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165 |
-0,075 |
-1,194 |
1,196 |
86,4 |
-0,1 |
3,9 |
3,8 |
17,17 |
17,38 |
17,45 |
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180 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,0 |
4,0 |
4,0 |
17,17461 |
17,07 |
17,15 |
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195 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,1 |
3,9 |
3,9 |
17,17 |
16,76 |
16,84 |
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210 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,1 |
3,5 |
3,6 |
17,16 |
16,48 |
16,54 |
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225 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,2 |
2,8 |
3,0 |
17,15 |
16,24 |
16,29 |
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240 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,2 |
2,0 |
2,2 |
17,14 |
16,06 |
16,09 |
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255 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,2 |
1,0 |
1,3 |
17,12 |
15,94 |
15,96 |
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270 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,3 |
0,0 |
0,3 |
17,10 |
15,91 |
15,90 |
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285 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,2 |
-1,0 |
-0,8 |
17,08 |
15,94 |
15,93 |
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300 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,2 |
-2,0 |
-1,8 |
17,06 |
16,06 |
16,02 |
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315 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,2 |
-2,8 |
-2,7 |
17,05 |
16,24 |
16,19 |
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330 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,1 |
-3,5 |
-3,3 |
17,03 |
16,48 |
16,42 |
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345 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,1 |
-3,9 |
-3,8 |
17,03 |
16,76 |
16,69 |
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360 |
-0,075 |
-1,194 |
1,196 |
86,4 |
0,0 |
-4,0 |
-4,0 |
17,10 |
17,07 |
17,00 |
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10. Wykresy dewiacji i sił ustawiajacych |
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11. Dyskusja wyników i wnioski . |
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MAGNETYZM OKRĘTOWY ZMIENNY |
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OBL.AUTOM. |
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OBL.MAN. |
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DEW ĆWIERĆOKRĘŻNA |
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TYP "D" , "E" , i TYP "A" |
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część ćwiczenia (1) |
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1. WYKONANIE OBSERWACJI |
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Na dewiaskopie ułożyć 2 poziome sztaby stali miekkiej +a i -d |
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dew: +D,-E,-A |
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1.1 Odczytać z odpowiedniej mapy magnetycznej wartość składowej poziomej i pionowej |
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magnetyzmu ziemskiego H i Z dla podanej pozycji geograficznej |
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1.2 Zdjąć charakterystykę całkowitej dewiacji półokrężnej |
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A |
B |
C |
D |
E |
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wywołanej magnetyzmem zmiennym |
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dc= |
f(KM) |
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2 |
5 |
4 |
2 |
1 |
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Wykonać obserwacje co 15 stopni dla cyrkulacji w prawo a następnie w lewo |
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W PRAWO |
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W LEWO |
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średnia |
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KM |
KK |
d1 |
KM |
KK |
d2 |
dc |
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KK |
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N |
0 |
-7 |
7,0 |
0 |
-7 |
7,0 |
7,0 |
j17 |
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-7 |
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7,0 |
-7,0 |
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0 |
7,0 |
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7,0 |
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15 |
6 |
9,0 |
15 |
6 |
9,0 |
9,0 |
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5,97617606554668 |
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9,0 |
6,0 |
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15 |
9,0 |
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9,0 |
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30 |
20 |
10,2 |
30 |
20 |
10,2 |
10,2 |
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19,8038475772934 |
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10,2 |
19,8 |
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30 |
10,2 |
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10,2 |
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NE |
45 |
35 |
10,4 |
45 |
35 |
10,4 |
10,4 |
j20 |
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34,6360389693211 |
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10,4 |
34,6 |
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45 |
10,4 |
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10,4 |
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60 |
50 |
9,6 |
60 |
50 |
9,6 |
9,6 |
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50,4378221735089 |
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9,6 |
50,4 |
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60 |
9,6 |
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9,6 |
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75 |
67 |
8,0 |
75 |
67 |
8,0 |
8,0 |
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67,001120091929 |
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8,0 |
67,0 |
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75 |
8,0 |
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8,0 |
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E |
90 |
84 |
6,0 |
90 |
84 |
6,0 |
6,0 |
j23 |
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84 |
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6,0 |
84,0 |
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90 |
6,0 |
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6,0 |
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105 |
101 |
3,9 |
105 |
101 |
3,9 |
3,9 |
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101,071672452749 |
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3,9 |
101,1 |
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105 |
3,9 |
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3,9 |
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120 |
118 |
2,1 |
120 |
118 |
2,1 |
2,1 |
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117,901923788647 |
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2,1 |
117,9 |
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120 |
2,1 |
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2,1 |
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SE |
135 |
134 |
0,7 |
135 |
134 |
0,7 |
0,7 |
j26 |
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134,292893218813 |
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0,7 |
134,3 |
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135 |
0,7 |
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0,7 |
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150 |
150 |
-0,2 |
150 |
150 |
-0,2 |
-0,2 |
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150,196152422707 |
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150,2 |
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150 |
-0,2 |
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-0,2 |
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165 |
166 |
-0,7 |
165 |
166 |
-0,7 |
-0,7 |
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165,703582675859 |
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-0,7 |
165,7 |
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165 |
-0,7 |
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S |
180 |
181 |
-1,0 |
180 |
181 |
-1,0 |
-1,0 |
j29 |
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181 |
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181,0 |
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180 |
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195 |
196 |
-1,3 |
195 |
196 |
-1,3 |
-1,3 |
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196,291773126884 |
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-1,3 |
196,3 |
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195 |
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210 |
212 |
-1,7 |
210 |
212 |
-1,7 |
-1,7 |
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211,732050807569 |
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-1,7 |
211,7 |
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210 |
-1,7 |
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-1,7 |
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SW |
225 |
227 |
-2,4 |
225 |
227 |
-2,4 |
-2,4 |
j32 |
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227,363961030679 |
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-2,4 |
227,4 |
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225 |
-2,4 |
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-2,4 |
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240 |
243 |
-3,1 |
240 |
243 |
-3,1 |
-3,1 |
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243,098076211353 |
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-3,1 |
243,1 |
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240 |
-3,1 |
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-3,1 |
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255 |
259 |
-3,7 |
255 |
259 |
-3,7 |
-3,7 |
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258,73093071564 |
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-3,7 |
258,7 |
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255 |
-3,7 |
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-3,7 |
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W |
270 |
274 |
-4,0 |
270 |
274 |
-4,0 |
-4,0 |
j35 |
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274 |
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-4,0 |
274,0 |
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270 |
-4,0 |
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-4,0 |
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285 |
289 |
-3,7 |
285 |
289 |
-3,7 |
-3,7 |
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288,66037835482 |
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-3,7 |
288,7 |
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285 |
-3,7 |
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-3,7 |
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300 |
303 |
-2,6 |
300 |
303 |
-2,6 |
-2,6 |
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302,562177826491 |
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-2,6 |
302,6 |
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300 |
-2,6 |
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-2,6 |
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NW |
315 |
316 |
-0,7 |
315 |
316 |
-0,7 |
-0,7 |
j38 |
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315,707106781187 |
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-0,7 |
315,7 |
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315 |
-0,7 |
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-0,7 |
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330 |
328 |
1,7 |
330 |
328 |
1,7 |
1,7 |
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328,267949192431 |
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1,7 |
328,3 |
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330 |
1,7 |
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1,7 |
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345 |
341 |
4,4 |
345 |
341 |
4,4 |
4,4 |
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340,564366516572 |
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4,4 |
340,6 |
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345 |
4,4 |
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4,4 |
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360 |
353 |
7,0 |
360 |
353 |
7,0 |
7,0 |
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353 |
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7,0 |
353,0 |
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360 |
7,0 |
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7,0 |
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zanotować (lub obliczyć) wartość składowej poziomej magnetyzmu Ziemii w warunkach statkowych Hm . |
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2. OPRACOWANIE POMIARÓW |
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1. Na podstawie danych z tabeli wykonać wykres dewiacji w funkcji kursu magnetycznego i kompasowego |
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dc= |
f(KM) |
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dc= |
f(KK) |
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2. Wyznaczyć współczynniki dewiacji D , E , A korzystając z zależności : |
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OBL.AUTOM. |
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OBL.MAN. |
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D = |
[( dNE + dSW ) - ( dSE + dNW )]/4 |
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2 |
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dE, dW,dN,ds. Itd.. |
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E = |
[( dN + dS ) - ( dE + dW )]/4 |
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1 |
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dewiacje zaobserwowane na kursach |
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A = |
[ dN + dNE + dE + dSE + dS + dSW + dW + dNW )] / 8 |
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2 |
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kompasowych E,W,N,S . Itd.. |
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3. Obliczyć wartość siły ustawiającej igłę kompasową w kierunku północy magnetycznej na statku, |
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korzystając z zależności : |
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Hm = k1 * H |
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gdzie k1 |
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współczynnik podany przez prowadzącego |
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k1 |
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0,95 |
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H |
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Hm |
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17,1 |
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4. Przedstawić na jednym wykresie (dla KK co 15 stopni) |
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dc D = |
D* sin(2KK) |
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dewiacja ćwierćokrężna typu D |
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dc(E+A) = |
A+ E* cos(2KK) |
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dewiacja ćwierćokrężna typu ( E+A) |
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dC = |
dc D + |
dc(E+A) |
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całkowita dewiacja ćwierćokrężna wywołana zmiennym polem magnetycznym okrętu |
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5. Obliczyć wartości sił: poprzecznej i wzdłużnej zaindukowanej w sztabach "a" oraz "d " w funkcji KK : f(KK). |
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Obliczenia wykonać dla KK od 0 do 360 stopni w odstępach co 15 stopni korzystając z zależności : |
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Fa = |
(Hm* sindc (D) ) / sin KK |
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D,E,A |
-w stopniach |
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Fd = |
(Hm* sindc (E+A) ) / cos KK |
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6. Obliczyć wartość składowej poziomej zmiennego magnetyzmu okrętowego M2 : |
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M3 = |
(Fa2 + Fd2)1/2 |
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7. Obliczenia z punktów 4, 5 , 6 zestawić w tabeli i przedstawić na wykresie : |
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KK |
dc(D) |
dc(E) |
dc(A) |
dc(E+A) |
dc =(D)+(E+A) |
Fa |
Fd |
M3 |
Uwagi |
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|
|
0 |
0,0 |
1,0 |
2,0 |
3,0 |
3,0 |
1,194 |
0,895 |
1,492 |
|
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15 |
1,0 |
0,9 |
2,0 |
2,9 |
3,9 |
1,153 |
0,885 |
1,454 |
|
|
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30 |
1,7 |
0,5 |
2,0 |
2,5 |
4,2 |
1,034 |
0,861 |
1,345 |
|
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45 |
2,0 |
0,0 |
2,0 |
2,0 |
4,0 |
0,844 |
0,844 |
1,194 |
|
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60 |
1,7 |
-0,5 |
2,0 |
1,5 |
3,2 |
0,597 |
0,895 |
1,076 |
|
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|
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75 |
1,0 |
-0,9 |
2,0 |
1,1 |
2,1 |
0,309 |
1,308 |
1,344 |
|
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90 |
0,0 |
-1,0 |
2,0 |
1,0 |
1,0 |
0,000 |
0,000 |
0,000 |
|
cos 90 |
0 |
|
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105 |
-1,0 |
-0,9 |
2,0 |
1,1 |
0,1 |
-0,309 |
-1,308 |
1,344 |
|
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120 |
-1,7 |
-0,5 |
2,0 |
1,5 |
-0,2 |
-0,597 |
-0,895 |
1,076 |
|
|
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135 |
-2,0 |
0,0 |
2,0 |
2,0 |
0,0 |
-0,844 |
-0,844 |
1,194 |
|
|
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|
150 |
-1,7 |
0,5 |
2,0 |
2,5 |
0,8 |
-1,034 |
-0,861 |
1,345 |
|
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|
165 |
-1,0 |
0,9 |
2,0 |
2,9 |
1,9 |
-1,153 |
-0,885 |
1,454 |
|
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180 |
0,0 |
1,0 |
2,0 |
3,0 |
3,0 |
-1,194 |
-0,895 |
1,492 |
|
|
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|
195 |
1,0 |
0,9 |
2,0 |
2,9 |
3,9 |
-1,153 |
-0,885 |
1,454 |
|
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|
210 |
1,7 |
0,5 |
2,0 |
2,5 |
4,2 |
-1,034 |
-0,861 |
1,345 |
|
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225 |
2,0 |
0,0 |
2,0 |
2,0 |
4,0 |
-0,844 |
-0,844 |
1,194 |
|
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240 |
1,7 |
-0,5 |
2,0 |
1,5 |
3,2 |
-0,597 |
-0,895 |
1,076 |
|
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|
255 |
1,0 |
-0,9 |
2,0 |
1,1 |
2,1 |
-0,309 |
-1,308 |
1,344 |
|
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|
270 |
0,0 |
-1,0 |
2,0 |
1,0 |
1,0 |
0,000 |
0,000 |
0,000 |
|
cos 270 |
0 |
|
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|
|
285 |
-1,0 |
-0,9 |
2,0 |
1,1 |
0,1 |
0,309 |
1,308 |
1,344 |
|
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|
300 |
-1,7 |
-0,5 |
2,0 |
1,5 |
-0,2 |
0,597 |
0,895 |
1,076 |
|
|
|
|
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|
|
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|
|
|
315 |
-2,0 |
0,0 |
2,0 |
2,0 |
0,0 |
0,844 |
0,844 |
1,194 |
|
|
|
|
|
|
|
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|
|
|
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|
|
330 |
-1,7 |
0,5 |
2,0 |
2,5 |
0,8 |
1,034 |
0,861 |
1,345 |
|
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|
|
345 |
-1,0 |
0,9 |
2,0 |
2,9 |
1,9 |
1,153 |
0,885 |
1,454 |
|
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360 |
0,0 |
1,0 |
2,0 |
3,0 |
3,0 |
1,194 |
0,895 |
1,492 |
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8. Obliczenia z tabeli przedstawić na wykresie : |
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9. Obliczyć wartości sil ustawiających Hk1, Hk2, Hk |
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gdzie Hk1, Hk2, Hk : |
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Obliczenia wykonać dla KK od 000 do 345 w odstępach co 15 stopni |
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Hk1 - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i Fa ) |
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Hk2 - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i Fd ) |
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Hk - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i M3 ) |
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9.1 |
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Hk1 = |
[ Hm * sin(KK + dc(D))] / [sin(KK)] |
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dla KK = 000 i 180 |
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Hk1 = Hm+ Fa |
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dla KK = 090 i 270 |
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Hk1 = Hm |
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17,1 |
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9.2 |
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Hk2 = |
[ Hm * cos(KK + dc(E+A))] / [ cos(KK)] |
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dla KK = 090 |
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Hk2 = Hm |
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17,1 |
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dla KK = 270 |
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Hk2 = Hm |
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17,1 |
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Hk = |
[M2*sin(KK + dpz + a)]/[sin(dpz)] |
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dla dpz = 0 |
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Hk = Hm + M2 |
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17,1 |
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jeżeli zwroty wektórow Hm i M2 są zgodne |
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Hk = |
[M2*sin(KK + dps + a)]/[sin(dps)] |
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+P , +Q |
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ODSTĘP |
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dla dpz = 0 |
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Hk = Hm - M2 |
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17,1 |
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jeżeli zwroty wektórow Hm i M2 są przeciwne |
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Hk = |
[M2*sin(KK + dps - a)]/[sin(dps)] |
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+P , -Q |
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Hk = |
[M2*sin((KK+ dps - a)]/[sin(dps)] |
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-P , +Q |
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Hk = |
[M2*sin((KK + dps + a)]/[sin(dps)] |
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-P , -Q |
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Zestaw Obliczeń pkt 8 i pkt 9 |
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KK |
Hm |
Fa |
Fd |
M3 |
dc(D) |
dc(E+A) |
Hk1 |
Hk2 |
Hk |
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0 |
17,100 |
1,194 |
0,895 |
1,5 |
0,0 |
3,0 |
18,294 |
17,08 |
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15 |
17,100 |
1,153 |
0,885 |
1,5 |
1,0 |
2,9 |
18,21 |
16,85 |
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30 |
17,100 |
1,034 |
0,861 |
1,3 |
1,7 |
2,5 |
17,99 |
16,65 |
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45 |
17,100 |
0,844 |
0,844 |
1,2 |
2,0 |
2,0 |
17,69 |
16,49 |
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60 |
17,100 |
0,597 |
0,895 |
1,1 |
1,7 |
1,5 |
17,39 |
16,32 |
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75 |
17,100 |
0,309 |
1,308 |
1,3 |
1,0 |
1,1 |
17,18 |
15,83 |
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90 |
17,100 |
0,000 |
0,000 |
0,0 |
0,0 |
1,0 |
17,10 |
17,10 |
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105 |
17,100 |
-0,309 |
-1,308 |
1,3 |
-1,0 |
1,1 |
17,18 |
18,36 |
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120 |
17,100 |
-0,597 |
-0,895 |
1,1 |
-1,7 |
1,5 |
17,39 |
17,87 |
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135 |
17,100 |
-0,844 |
-0,844 |
1,2 |
-2,0 |
2,0 |
17,69 |
17,69 |
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150 |
17,100 |
-1,034 |
-0,861 |
1,3 |
-1,7 |
2,5 |
17,99 |
17,51 |
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165 |
17,100 |
-1,153 |
-0,885 |
1,5 |
-1,0 |
2,9 |
18,21 |
17,31 |
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180 |
17,100 |
-1,194 |
-0,895 |
1,5 |
0,0 |
3,0 |
15,906 |
17,08 |
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195 |
17,100 |
-1,153 |
-0,885 |
1,5 |
1,0 |
2,9 |
18,21 |
16,85 |
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210 |
17,100 |
-1,034 |
-0,861 |
1,3 |
1,7 |
2,5 |
17,99 |
16,65 |
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|
|
|
|
225 |
17,100 |
-0,844 |
-0,844 |
1,2 |
2,0 |
2,0 |
17,69 |
16,49 |
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240 |
17,100 |
-0,597 |
-0,895 |
1,1 |
1,7 |
1,5 |
17,39 |
16,32 |
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255 |
17,100 |
-0,309 |
-1,308 |
1,3 |
1,0 |
1,1 |
17,18 |
15,83 |
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270 |
17,100 |
0,000 |
0,000 |
0,0 |
0,0 |
1,0 |
17,10 |
17,10 |
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285 |
17,100 |
0,309 |
1,308 |
1,3 |
-1,0 |
1,1 |
17,18 |
18,36 |
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300 |
17,100 |
0,597 |
0,895 |
1,1 |
-1,7 |
1,5 |
17,39 |
17,87 |
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315 |
17,100 |
0,844 |
0,844 |
1,2 |
-2,0 |
2,0 |
17,69 |
17,69 |
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330 |
17,100 |
1,034 |
0,861 |
1,3 |
-1,7 |
2,5 |
17,99 |
17,51 |
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345 |
17,100 |
1,153 |
0,885 |
1,5 |
-1,0 |
2,9 |
18,21 |
17,31 |
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360 |
17,100 |
1,194 |
0,895 |
1,5 |
0,0 |
3,0 |
17,10 |
17,08 |
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10. Wykresy sił ustawiajacych |
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Wykres siły Hk przedstawić na podstawie przebiegów składowych Hk1 oraz Hk2 |
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11. Dyskusja wyników i wnioski . |
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MAGNETYZM OKRĘTOWY ZMIENNY |
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OBL.AUTOM. |
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OBL.MAN. |
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DEW ĆWIERĆOKRĘŻNA |
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TYP "D" , "E" , i TYP "A" |
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część ćwiczenia (2) |
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1. WYKONANIE OBSERWACJI |
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Na dewiaskopie ułożyć 2 poziome sztaby stali miekkiej -e i +d |
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dew: +D,-E,-A |
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1.1 Odczytać z odpowiedniej mapy magnetycznej wartość składowej poziomej i pionowej |
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magnetyzmu ziemskiego H i Z dla podanej pozycji geograficznej |
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1.2 Zdjąć charakterystykę całkowitej dewiacji półokrężnej |
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A |
B |
C |
D |
E |
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wywołanej magnetyzmem zmiennym |
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dc= |
f(KM) |
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2 |
5 |
4 |
2 |
1 |
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Wykonać obserwacje co 15 stopni dla cyrkulacji w prawo a następnie w lewo |
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W PRAWO |
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W LEWO |
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średnia |
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KM |
KK |
d1 |
KM |
KK |
d2 |
dc |
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KK |
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N |
0 |
-7 |
7,0 |
0 |
-7 |
7,0 |
7,0 |
j17 |
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-7 |
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7 |
-7,0 |
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0 |
7,0 |
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7,0 |
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15 |
6 |
9,0 |
15 |
6 |
9,0 |
9,0 |
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5,97617606554668 |
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9,02382393445332 |
6,0 |
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15 |
9,0 |
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9,0 |
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30 |
20 |
10,2 |
30 |
20 |
10,2 |
10,2 |
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19,8038475772934 |
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10,1961524227066 |
19,8 |
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30 |
10,2 |
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10,2 |
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NE |
45 |
35 |
10,4 |
45 |
35 |
10,4 |
10,4 |
j20 |
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34,6360389693211 |
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10,3639610306789 |
34,6 |
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45 |
10,4 |
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10,4 |
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60 |
50 |
9,6 |
60 |
50 |
9,6 |
9,6 |
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50,4378221735089 |
|
9,56217782649107 |
50,4 |
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60 |
9,6 |
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9,6 |
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75 |
67 |
8,0 |
75 |
67 |
8,0 |
8,0 |
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67,001120091929 |
|
7,99887990807099 |
67,0 |
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75 |
8,0 |
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8,0 |
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E |
90 |
84 |
6,0 |
90 |
84 |
6,0 |
6,0 |
j23 |
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84 |
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6 |
84,0 |
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90 |
6,0 |
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6,0 |
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105 |
101 |
3,9 |
105 |
101 |
3,9 |
3,9 |
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101,071672452749 |
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3,92832754725082 |
101,1 |
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105 |
3,9 |
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3,9 |
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120 |
118 |
2,1 |
120 |
118 |
2,1 |
2,1 |
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117,901923788647 |
|
2,09807621135332 |
117,9 |
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120 |
2,1 |
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2,1 |
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SE |
135 |
134 |
0,7 |
135 |
134 |
0,7 |
0,7 |
j26 |
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134,292893218813 |
|
0,707106781186548 |
134,3 |
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135 |
0,7 |
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0,7 |
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150 |
150 |
-0,2 |
150 |
150 |
-0,2 |
-0,2 |
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150,196152422707 |
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-0,196152422706632 |
150,2 |
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150 |
-0,2 |
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-0,2 |
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165 |
166 |
-0,7 |
165 |
166 |
-0,7 |
-0,7 |
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165,703582675859 |
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-0,70358267585923 |
165,7 |
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165 |
-0,7 |
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-0,7 |
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S |
180 |
181 |
-1,0 |
180 |
181 |
-1,0 |
-1,0 |
j29 |
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181 |
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-1 |
181,0 |
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180 |
-1,0 |
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-1,0 |
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195 |
196 |
-1,3 |
195 |
196 |
-1,3 |
-1,3 |
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196,291773126884 |
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-1,29177312688444 |
196,3 |
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195 |
-1,3 |
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-1,3 |
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210 |
212 |
-1,7 |
210 |
212 |
-1,7 |
-1,7 |
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211,732050807569 |
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-1,73205080756888 |
211,7 |
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210 |
-1,7 |
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-1,7 |
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SW |
225 |
227 |
-2,4 |
225 |
227 |
-2,4 |
-2,4 |
j32 |
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227,363961030679 |
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-2,36396103067893 |
227,4 |
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225 |
-2,4 |
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-2,4 |
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240 |
243 |
-3,1 |
240 |
243 |
-3,1 |
-3,1 |
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243,098076211353 |
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-3,09807621135331 |
243,1 |
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240 |
-3,1 |
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-3,1 |
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255 |
259 |
-3,7 |
255 |
259 |
-3,7 |
-3,7 |
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258,73093071564 |
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-3,73093071563986 |
258,7 |
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255 |
-3,7 |
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-3,7 |
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W |
270 |
274 |
-4,0 |
270 |
274 |
-4,0 |
-4,0 |
j35 |
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274 |
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-4 |
274,0 |
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270 |
-4,0 |
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-4,0 |
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285 |
289 |
-3,7 |
285 |
289 |
-3,7 |
-3,7 |
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288,66037835482 |
|
-3,6603783548197 |
288,7 |
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285 |
-3,7 |
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-3,7 |
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300 |
303 |
-2,6 |
300 |
303 |
-2,6 |
-2,6 |
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302,562177826491 |
|
-2,56217782649107 |
302,6 |
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300 |
-2,6 |
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-2,6 |
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NW |
315 |
316 |
-0,7 |
315 |
316 |
-0,7 |
-0,7 |
j38 |
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315,707106781187 |
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-0,70710678118655 |
315,7 |
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315 |
-0,7 |
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-0,7 |
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330 |
328 |
1,7 |
330 |
328 |
1,7 |
1,7 |
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328,267949192431 |
|
1,73205080756887 |
328,3 |
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330 |
1,7 |
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1,7 |
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345 |
341 |
4,4 |
345 |
341 |
4,4 |
4,4 |
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340,564366516572 |
|
4,43563348342811 |
340,6 |
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345 |
4,4 |
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4,4 |
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360 |
353 |
7,0 |
360 |
353 |
7,0 |
7,0 |
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353 |
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7 |
353,0 |
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360 |
7,0 |
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7,0 |
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zanotować (lub obliczyć) wartość składowej poziomej magnetyzmu Ziemii w warunkach statkowych Hm . |
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2. OPRACOWANIE POMIARÓW |
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1. Na podstawie danych z tabeli wykonać wykres dewiacji w funkcji kursu magnetycznego i kompasowego |
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dc= |
f(KM) |
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dc= |
f(KK) |
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2. Wyznaczyć współczynniki dewiacji D , E , A korzystając z zależności : |
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OBL.AUTOM. |
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OBL.MAN. |
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D = |
[( dNE + dSW ) - ( dSE + dNW )]/4 |
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2 |
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dE, dW,dN,ds. Itd.. |
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E = |
[( dN + dS ) - ( dE + dW )]/4 |
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1 |
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dewiacje zaobserwowane na kursach |
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A = |
[ dN + dNE + dE + dSE + dS + dSW + dW + dNW )] / 8 |
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2 |
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kompasowych E,W,N,S . Itd.. |
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3. Obliczyć wartość siły ustawiającej igłę kompasową w kierunku północy magnetycznej na statku, |
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korzystając z zależności : |
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Hm = k1 * H |
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gdzie k1 |
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współczynnik podany przez prowadzącego |
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k1 |
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0,95 |
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H |
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Hm |
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17,1 |
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4. Przedstawić na jednym wykresie (dla KK co 15 stopni) |
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dc D = |
D* sin(2KK) |
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dewiacja ćwierćokrężna typu D |
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dc(E+A) = |
A+ E* cos(2KK) |
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dewiacja ćwierćokrężna typu ( E+A) |
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dC = |
dc D + |
dc(E+A) |
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całkowita dewiacja ćwierćokrężna wywołana zmiennym polem magnetycznym okrętu |
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5. Obliczyć wartości sił: poprzecznej i wzdłużnej zaindukowanej w sztabach "e" oraz "d " w funkcji KK : f(KK). |
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Obliczenia wykonać dla KK od 0 do 360 stopni w odstępach co 15 stopni korzystając z zależności : |
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Fe = |
(Hm* sindc (D) ) / cos KK |
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D,E,A |
-w stopniach |
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Fd = |
(Hm* sindc (E+A) ) / cos KK |
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6. Obliczyć wartość składowej poziomej zmiennego magnetyzmu okrętowego M2 : |
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M4 = |
Fe + Fd |
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7. Obliczenia z punktów 4, 5 , 6 zestawić w tabeli i przedstawić na wykresie : |
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-e |
+d |
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KK |
dc(D) |
dc(E) |
dc(A) |
dc(E+A) |
dc =(D)+(E+A) |
Fe |
Fd |
M4 |
Uwagi |
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0 |
0,0 |
1,0 |
2,0 |
3,0 |
3,0 |
0,000 |
0,895 |
0,895 |
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15 |
1,0 |
0,9 |
2,0 |
2,9 |
3,9 |
0,309 |
0,885 |
1,194 |
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30 |
1,7 |
0,5 |
2,0 |
2,5 |
4,2 |
0,597 |
0,861 |
1,458 |
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45 |
2,0 |
0,0 |
2,0 |
2,0 |
4,0 |
0,844 |
0,844 |
1,688 |
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60 |
1,7 |
-0,5 |
2,0 |
1,5 |
3,2 |
1,034 |
0,895 |
1,929 |
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75 |
1,0 |
-0,9 |
2,0 |
1,1 |
2,1 |
1,153 |
1,308 |
2,461 |
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90 |
0,0 |
-1,0 |
2,0 |
1,0 |
1,0 |
1,194 |
0,000 |
1,194 |
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cos 90 |
0 |
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105 |
-1,0 |
-0,9 |
2,0 |
1,1 |
0,1 |
1,153 |
-1,308 |
-0,154 |
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120 |
-1,7 |
-0,5 |
2,0 |
1,5 |
-0,2 |
1,034 |
-0,895 |
0,138 |
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135 |
-2,0 |
0,0 |
2,0 |
2,0 |
0,0 |
0,844 |
-0,844 |
0,000 |
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150 |
-1,7 |
0,5 |
2,0 |
2,5 |
0,8 |
0,597 |
-0,861 |
-0,264 |
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165 |
-1,0 |
0,9 |
2,0 |
2,9 |
1,9 |
0,309 |
-0,885 |
-0,576 |
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180 |
0,0 |
1,0 |
2,0 |
3,0 |
3,0 |
0,000 |
-0,895 |
-0,895 |
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195 |
1,0 |
0,9 |
2,0 |
2,9 |
3,9 |
-0,309 |
-0,885 |
-1,194 |
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210 |
1,7 |
0,5 |
2,0 |
2,5 |
4,2 |
-0,597 |
-0,861 |
-1,458 |
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225 |
2,0 |
0,0 |
2,0 |
2,0 |
4,0 |
-0,844 |
-0,844 |
-1,688 |
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240 |
1,7 |
-0,5 |
2,0 |
1,5 |
3,2 |
-1,034 |
-0,895 |
-1,929 |
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255 |
1,0 |
-0,9 |
2,0 |
1,1 |
2,1 |
-1,153 |
-1,308 |
-2,461 |
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270 |
0,0 |
-1,0 |
2,0 |
1,0 |
1,0 |
-1,194 |
0,000 |
-1,194 |
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cos 270 |
0 |
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285 |
-1,0 |
-0,9 |
2,0 |
1,1 |
0,1 |
-1,153 |
1,308 |
0,154 |
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300 |
-1,7 |
-0,5 |
2,0 |
1,5 |
-0,2 |
-1,034 |
0,895 |
-0,138 |
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315 |
-2,0 |
0,0 |
2,0 |
2,0 |
0,0 |
-0,844 |
0,844 |
0,000 |
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330 |
-1,7 |
0,5 |
2,0 |
2,5 |
0,8 |
-0,597 |
0,861 |
0,264 |
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345 |
-1,0 |
0,9 |
2,0 |
2,9 |
1,9 |
-0,309 |
0,885 |
0,576 |
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360 |
0,0 |
1,0 |
2,0 |
3,0 |
3,0 |
0,000 |
0,895 |
0,895 |
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8. Obliczenia z tabeli przedstawić na wykresie : |
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9. Obliczyć wartości sil ustawiających Hk1, Hk2, Hk |
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gdzie Hk1, Hk2, Hk : |
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Obliczenia wykonać dla KK od 000 do 345 w odstępach co 15 stopni |
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Hk1 - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i Fe ) |
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Hk2 - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i Fd ) |
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Hk - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i M4 ) |
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9.1 |
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Hk1 = |
[ Hm * cos(KK + dc(D))] / [cos(KK)] |
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dla KK = 090 i 270 |
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Hk1 = Hm - Fe |
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9.2 |
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Hk2 = |
[ Hm * cos(KK + dc(E+A))] / [ cos(KK)] |
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dla KK = 090 |
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Hk2 = Hm |
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17,1 |
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dla KK = 270 |
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Hk2 = Hm |
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17,1 |
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9.3 |
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Hk = |
[Hm*cos(KK + dc] / [cos(KK)] |
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dla KK = 090 |
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Hk = Hm - M4 |
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+P , +Q |
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+P , -Q |
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dla KK = 270 |
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Hk = Hm - M4 |
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-P , +Q |
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-P , -Q |
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Zestaw Obliczeń pkt 8 i pkt 9 |
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KK |
Hm |
Fe |
Fd |
M4 |
dc(D) |
dc(E+A) |
dc =(D)+(E+A) |
Hk1 |
Hk2 |
Hk |
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0 |
17,100 |
0,000 |
0,895 |
0,9 |
0,0 |
3,0 |
3,0 |
17,10 |
17,08 |
16,80 |
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15 |
17,100 |
0,309 |
0,885 |
1,2 |
1,0 |
2,9 |
3,9 |
17,02 |
16,85 |
16,71 |
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30 |
17,100 |
0,597 |
0,861 |
1,5 |
1,7 |
2,5 |
4,2 |
16,79 |
16,65 |
16,67 |
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45 |
17,100 |
0,844 |
0,844 |
1,7 |
2,0 |
2,0 |
4,0 |
16,49 |
16,49 |
16,69 |
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60 |
17,100 |
1,034 |
0,895 |
1,9 |
1,7 |
1,5 |
3,2 |
16,20 |
16,32 |
16,78 |
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75 |
17,100 |
1,153 |
1,308 |
2,5 |
1,0 |
1,1 |
2,1 |
15,98 |
15,83 |
16,89 |
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90 |
17,100 |
1,194 |
0,000 |
1,2 |
0,0 |
1,0 |
1,0 |
15,91 |
17,10 |
17,01 |
15,906 |
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105 |
17,100 |
1,153 |
-1,308 |
-0,2 |
-1,0 |
1,1 |
0,1 |
15,98 |
18,36 |
17,09 |
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120 |
17,100 |
1,034 |
-0,895 |
0,1 |
-1,7 |
1,5 |
-0,2 |
16,20 |
17,87 |
17,12 |
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135 |
17,100 |
0,844 |
-0,844 |
0,0 |
-2,0 |
2,0 |
0,0 |
16,49 |
17,69 |
17,10 |
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150 |
17,100 |
0,597 |
-0,861 |
-0,3 |
-1,7 |
2,5 |
0,8 |
16,79 |
17,51 |
17,03 |
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165 |
17,100 |
0,309 |
-0,885 |
-0,6 |
-1,0 |
2,9 |
1,9 |
17,02 |
17,31 |
16,92 |
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180 |
17,100 |
0,000 |
-0,895 |
-0,9 |
0,0 |
3,0 |
3,0 |
17,10 |
17,08 |
16,80 |
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195 |
17,100 |
-0,309 |
-0,885 |
-1,2 |
1,0 |
2,9 |
3,9 |
17,02 |
16,85 |
16,71 |
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210 |
17,100 |
-0,597 |
-0,861 |
-1,5 |
1,7 |
2,5 |
4,2 |
16,79 |
16,65 |
16,67 |
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225 |
17,100 |
-0,844 |
-0,844 |
-1,7 |
2,0 |
2,0 |
4,0 |
16,49 |
16,49 |
16,69 |
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240 |
17,100 |
-1,034 |
-0,895 |
-1,9 |
1,7 |
1,5 |
3,2 |
16,20 |
16,32 |
16,78 |
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255 |
17,100 |
-1,153 |
-1,308 |
-2,5 |
1,0 |
1,1 |
2,1 |
15,98 |
15,83 |
16,89 |
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270 |
17,100 |
-1,194 |
0,000 |
-1,2 |
0,0 |
1,0 |
1,0 |
18,29 |
17,10 |
17,01 |
18,294 |
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285 |
17,100 |
-1,153 |
1,308 |
0,2 |
-1,0 |
1,1 |
0,1 |
15,98 |
18,36 |
17,09 |
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300 |
17,100 |
-1,034 |
0,895 |
-0,1 |
-1,7 |
1,5 |
-0,2 |
16,20 |
17,87 |
17,12 |
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315 |
17,100 |
-0,844 |
0,844 |
0,0 |
-2,0 |
2,0 |
0,0 |
16,49 |
17,69 |
17,10 |
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330 |
17,100 |
-0,597 |
0,861 |
0,3 |
-1,7 |
2,5 |
0,8 |
16,79 |
17,51 |
17,03 |
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345 |
17,100 |
-0,309 |
0,885 |
0,6 |
-1,0 |
2,9 |
1,9 |
17,02 |
17,31 |
16,92 |
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360 |
17,100 |
0,000 |
0,895 |
0,9 |
0,0 |
3,0 |
3,0 |
17,10 |
17,08 |
16,80 |
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10. Wykresy sił ustawiajacych |
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Wykres siły Hk przedstawić na podstawie przebiegów składowych Hk1 oraz Hk2 |
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11. Dyskusja wyników i wnioski . |
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MAGNETYZM STAŁY |
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OBL.AUTOM. |
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OBL.MAN. |
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DEWIACJA PÓŁOKRĘŻNA |
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TYP: B1 , C1 |
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1. WYKONANIE OBSERWACJI |
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1.1 Odczytać z odpowiedniej mapy magnetycznej wartość składowej poziomej |
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magnetyzmu ziemskiego H dla podanej pozycji geograficznej |
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1.2 Zdjąć charakterystykę całkowitej dewiacji pół okrężnej |
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wywołanej magnetyzmem stałym |
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w funkcji (KM). Wykonać obserwacje co 15 stopni dla cyrkulacji w prawo a następnie w lewo |
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W PRAWO |
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W LEWO |
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-2 |
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KM |
KK |
d1 |
KM |
KK |
d2 |
dśrednia |
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KK |
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0 |
9 |
-9 |
0 |
11 |
-11 |
-10 |
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-11 |
0 |
11 |
10 |
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15 |
23 |
-8 |
15 |
25 |
-10 |
-9 |
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-10 |
15 |
25 |
24 |
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30 |
37 |
-7 |
30 |
39 |
-9 |
-8 |
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-9 |
30 |
39 |
38 |
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45 |
51 |
-6 |
45 |
53 |
-8 |
-7 |
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-8 |
45 |
53 |
52 |
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60 |
65 |
-5 |
60 |
67 |
-7 |
-6 |
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-7 |
60 |
67 |
66 |
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75 |
79 |
-4 |
75 |
81 |
-6 |
-5 |
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-6 |
75 |
81 |
80 |
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90 |
93 |
-3 |
90 |
95 |
-5 |
-4 |
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-5 |
90 |
95 |
94 |
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105 |
107 |
-2 |
105 |
109 |
-4 |
-3 |
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-4 |
105 |
109 |
108 |
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120 |
121 |
-1 |
120 |
123 |
-3 |
-2 |
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-3 |
120 |
123 |
122 |
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135 |
135 |
0 |
135 |
137 |
-2 |
-1 |
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-2 |
135 |
137 |
136 |
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150 |
149 |
1 |
150 |
151 |
-1 |
0 |
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-1 |
150 |
151 |
150 |
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165 |
163 |
2 |
165 |
165 |
0 |
1 |
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0 |
165 |
165 |
164 |
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180 |
177 |
3 |
180 |
179 |
1 |
2 |
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1 |
180 |
179 |
178 |
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195 |
191 |
4 |
195 |
193 |
2 |
3 |
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2 |
195 |
193 |
192 |
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210 |
205 |
5 |
210 |
207 |
3 |
4 |
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3 |
210 |
207 |
206 |
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225 |
219 |
6 |
225 |
221 |
4 |
5 |
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4 |
225 |
221 |
220 |
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240 |
235 |
5 |
240 |
235 |
5 |
5 |
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5 |
240 |
235 |
235 |
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255 |
251 |
4 |
255 |
249 |
6 |
5 |
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6 |
255 |
249 |
250 |
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270 |
268 |
2 |
270 |
265 |
5 |
3,5 |
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5 |
270 |
265 |
266,5 |
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285 |
283 |
2 |
285 |
281 |
4 |
3 |
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4 |
285 |
281 |
282 |
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300 |
299 |
1 |
300 |
297 |
3 |
2 |
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3 |
300 |
297 |
298 |
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315 |
315 |
0 |
315 |
313 |
2 |
1 |
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2 |
315 |
313 |
314 |
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330 |
331 |
-1 |
330 |
329 |
1 |
0 |
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1 |
330 |
329 |
330 |
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345 |
347 |
-2 |
345 |
345 |
0 |
-1 |
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0 |
345 |
345 |
346 |
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360 |
363 |
-3 |
360 |
361 |
-1 |
-2 |
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-1 |
360 |
361 |
362 |
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1.3 Wyznaczyć empirycznie kurs magnetyczny budowy statku |
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a |
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(poszukać KM, dla którego dewiacja jest równa zeru). |
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2. OPRACOWANIE POMIARÓW |
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1. Na podstawie danych z tabeli wykonać wykres dewiacji w funkcji kursu magnetycznego i kompasowego |
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dps= |
f(KM) |
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dps= |
f(KK) |
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2. Wyznaczyć współczynniki dewiacji B1 oraz C1 korzystając z zależności : |
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OBL.AUTOM. |
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OBL.MAN. |
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B1= |
( dE - dW )/2 |
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-0,25 |
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dE, dW,dN,dS |
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C1= |
( dN - dS )/2 |
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-4 |
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dewiacje zaobserwowane na kursach |
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kompasowych E,W,N,S . |
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3. Obliczyć wartość siły ustawiającej igłę kompasową w kierunku północy magnetycznej na statku, |
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korzystając z zależności : |
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Hm = k1 * H |
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gdzie k1 |
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współczynnik podany przez prowadzącego |
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k1 |
= |
0,95 |
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H |
= |
17,3 |
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Hm |
= |
16,435 |
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4. Obliczyć wartość składowej wzdłużnej |
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stałego magnetyzmu okrętowego P1 oraz |
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wartość składowej poprzecznej stałego magnetyzmu okrętowego Q1 : |
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P1 = |
(B1* Hm)/57,3 |
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-0,071705933682374 |
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B1, C1 |
-w stopniach |
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Q1 = |
(C1* Hm)/57,3 |
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-1,14729493891798 |
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5. Wyznaczyć analitycznie kurs budowy statku |
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a |
i porównać jego |
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wartość z wynikiem pomiaru uzyskanym uprzednio |
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-P1 |
+Q1 |
a |
NE |
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+P1 |
+Q1 |
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SE |
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a |
= arctg[IQ1I/IP1I] |
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ABS Q1= |
1,14729493891798 |
Q1 = |
-1,19371727748691 |
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+P1 |
-Q1 |
a |
SW |
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ABS P1= |
0,071705933682374 |
P1 = |
-0,074607329842932 |
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-P1 |
-Q1 |
a |
NW |
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a |
86,4236656250027 |
a |
273,576334374997 |
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7.Obliczyć wartość składowej poziomej stałego magnetyzmu okrętowego M1 : |
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M1 = |
(P12 + Q12)1/2 |
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1,14953356531772 |
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8. Przedstawić na jednym wykresie (dla KK co 15 stopni) |
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dpsB1= |
B1* sin(KK) |
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dewiacja półokrężna typu B1 |
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dpsC1= |
C1* cos(KK) |
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dewiacja półokrężna typu C1 |
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9. Obliczyć wartości sil ustawiających Hk1, Hk2, Hk |
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gdzie Hk1, Hk2, Hk : |
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Obliczenia wykonać dla KK od 000 do 345 w odstępach co 15 stopni |
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Hk1 - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i P1) |
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Hk2 - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i Q1) |
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Hk - wartość średniej sily ustawiającej igłę kompasową (wypadkowa z Hm i M1) |
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9.1 |
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Hk1 = |
[P1*sin(KK + dps(B1))]/[sin(dps(B1))] |
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dla KK = 000 |
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Hk1 = Hm+ P1 |
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16,3632940663176 |
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dla KK = 180 |
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Hk1 = HM - P1 |
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16,5067059336824 |
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9.2 |
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Hk2 = |
[Q1*cos(KK + dps(C1))]/[sin(dps(C1))] |
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dla KK = 090 |
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Hk2 = Hm - Q1 |
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17,582294938918 |
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dla KK = 270 |
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Hk2 = HM + Q1 |
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15,287705061082 |
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9.3 |
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Hk = |
[M1*sin(KK + dps + a)]/[sin(dps)] |
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dla dps = 0 |
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Hk = Hm + M1 |
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17,5845335653177 |
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jeżeli zwroty wektórow Hm i M1 są zgodne |
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Hk = |
[M1*sin(KK + dps + a)]/[sin(dps)] |
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+P , +Q |
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dla dps = 0 |
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Hk = Hm - M1 |
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15,2854664346823 |
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jeżeli zwroty wektórow Hm i M1 są przeciwne |
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Hk = |
[M1*sin(KK + dps - a)]/[sin(dps)] |
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+P , -Q |
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Hk = |
[M1*sin((KK+ dps - a)]/[sin(dps)] |
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-P , +Q |
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Hk = |
[M1*sin((KK + dps + a)]/[sin(dps)] |
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-P , -Q |
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Zestaw Obliczeń pkt 8 i pkt 9 |
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KK |
P1 |
Q1 |
M1 |
a |
dpsB1 |
dpsC1 |
dps |
Hk1 |
Hk2 |
Hk |
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0 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,0 |
-4,0 |
-4,0 |
16,3632940663176 |
16,41 |
16,34 |
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15 |
-0,072 |
-1,147 |
1,150 |
86,4 |
-0,1 |
-3,9 |
-3,9 |
16,36 |
16,71 |
16,64 |
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30 |
-0,072 |
-1,147 |
1,150 |
86,4 |
-0,1 |
-3,5 |
-3,6 |
16,37 |
16,99 |
16,92 |
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45 |
-0,072 |
-1,147 |
1,150 |
86,4 |
-0,2 |
-2,8 |
-3,0 |
16,38 |
17,23 |
17,18 |
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60 |
-0,072 |
-1,147 |
1,150 |
86,4 |
-0,2 |
-2,0 |
-2,2 |
16,40 |
17,42 |
17,38 |
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75 |
-0,072 |
-1,147 |
1,150 |
86,4 |
-0,2 |
-1,0 |
-1,3 |
16,42 |
17,54 |
17,52 |
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90 |
-0,072 |
-1,147 |
1,150 |
86,4 |
-0,3 |
0,0 |
-0,3 |
16,43 |
17,58 |
17,58 |
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105 |
-0,072 |
-1,147 |
1,150 |
86,4 |
-0,2 |
1,0 |
0,8 |
16,45 |
17,54 |
17,56 |
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120 |
-0,072 |
-1,147 |
1,150 |
86,4 |
-0,2 |
2,0 |
1,8 |
16,47 |
17,42 |
17,46 |
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135 |
-0,072 |
-1,147 |
1,150 |
86,4 |
-0,2 |
2,8 |
2,7 |
16,48 |
17,23 |
17,28 |
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150 |
-0,072 |
-1,147 |
1,150 |
86,4 |
-0,1 |
3,5 |
3,3 |
16,50 |
16,99 |
17,05 |
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165 |
-0,072 |
-1,147 |
1,150 |
86,4 |
-0,1 |
3,9 |
3,8 |
16,50 |
16,71 |
16,78 |
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180 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,0 |
4,0 |
4,0 |
16,50671 |
16,41 |
16,48 |
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195 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,1 |
3,9 |
3,9 |
16,50 |
16,11 |
16,18 |
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210 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,1 |
3,5 |
3,6 |
16,50 |
15,84 |
15,90 |
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225 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,2 |
2,8 |
3,0 |
16,48 |
15,61 |
15,66 |
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240 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,2 |
2,0 |
2,2 |
16,47 |
15,43 |
15,47 |
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255 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,2 |
1,0 |
1,3 |
16,45 |
15,32 |
15,34 |
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|
|
|
|
|
|
|
270 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,3 |
0,0 |
0,3 |
16,43 |
15,29 |
15,29 |
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|
|
|
|
|
|
|
285 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,2 |
-1,0 |
-0,8 |
16,42 |
15,32 |
15,31 |
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|
300 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,2 |
-2,0 |
-1,8 |
16,40 |
15,43 |
15,40 |
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|
315 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,2 |
-2,8 |
-2,7 |
16,38 |
15,61 |
15,56 |
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|
330 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,1 |
-3,5 |
-3,3 |
16,37 |
15,84 |
15,78 |
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345 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,1 |
-3,9 |
-3,8 |
16,36 |
16,11 |
16,04 |
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360 |
-0,072 |
-1,147 |
1,150 |
86,4 |
0,0 |
-4,0 |
-4,0 |
16,43 |
16,41 |
16,34 |
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10. Wykresy dewiacji i sił ustawiajacych |
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11. Dyskusja wyników i wnioski . |
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