p35 052

background image

52.

(a) First, the lens forms a real image of the object located at a distance

i

1

=

1

f

1

1

p

1

1

=

1

f

1

1

2f

1

1

= 2f

1

to the right of the lens, or at p

2

= 2(f

1

+ f

2

)

2f

1

= 2f

2

in front of the mirror. The subsequent

image formed by the mirror is located at a distance

i

2

=

1

f

2

1

p

2

1

=

1

f

2

1

2f

2

1

= 2f

2

to the left of the mirror, or at p

1

= 2(f

1

+ f

2

)

2f

2

= 2f

1

to the right of the lens. The final image

formed by the lens is that at a distance i

1

to the left of the lens, where

i

1

=

1

f

1

1

p

1

1

=

1

f

1

1

2f

1

1

= 2f

1

.

This turns out to be the same as the location of the original object. The final image is real and
inverted. The lateral magnification is

m =

i

1

p

1

i

2

p

2

i

1

p

1

=

2f

1

2f

1

2f

2

2f

2

2f

1

2f

1

=

1.0 .

(b) The ray diagram is shown below. We set the ratio f

2

/f

1

= 1/2 for the purposes of this sketch. The

intermediate images are not shown explicitly, but they are both located on the plane indicated by
the dashed line.

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