ObciΔ ΕΌenie Εniegiem dachu wg normy PN-EN 1991-1-3
Snβ=βuiβ
*β
Ceβ
*β
Cfβ
*β
Sk
uiβ
ββ
Β wspolczynnikΒ ksztaltuΒ dachu
Ceβ
ββ
Β wspolczynnikΒ ekspozycjiβ=β1,β0
Β Cfβ
ββ
Β wspolczynnikΒ termicznyβ=β1,β0
$$S_{k} - \ wartosc\ charakterystyczna\ obciazenia\ sniegiem\ gruntu,\ \frac{\text{kN}}{m^{2}}$$
Ξ±=42Β° β $u_{i} = 0,8*\frac{(60 - \alpha)}{30} = 0,48$
Ceβ=β1,β0
Cfβ=β1,β0
Opole, strefa II β$S_{k} = 0,9\frac{\text{kN}}{m^{2}}$
$S_{k} = 0,48*1,0*1,0*0,9 = 0,432\frac{\text{kN}}{m^{2}}$
Qβ=β1,β5
$S_{d} = S_{k}*_{Q} = 0,432*1,5 = 0,648\frac{\text{kN}}{m^{2}}$
ObciΔ ΕΌenie | Sk |
f |
Sd |
---|---|---|---|
ObciΔ ΕΌenie Εniegiem na 1 m2rzutu poΕaci dachowej: |
|
|
OddziaΕywanie wiatru wg normy PN-EN 1991-1-4
lokalizacjaβ ββ Opole
szerokoscΒ polaciΒ dachowejβ ββ 9,β95Β m
dlugoscΒ polaciΒ dachowejβ ββ 12,β88Β mΒ
wysokoscΒ budynkuΒ nadΒ poziomemΒ terenu,βΒ zβ=βhβ=β8,β05Β mΒ
Bazowa prΔdkoΕΔ wiatru.
Vbβ=βCdirβ
*β
Cseasonβ
*β
Vb,β0
Cdirβ=β1,β0
Cseasonβ=β1,β0
Opole, strefa I, A~157 m.n.p.m < 300 m.n.p.m
Vbβ=β1,β0β
*β
1,β0β
*β
Vb,β0
$$V_{b,0} = 22\frac{m}{s}$$
$$\mathbf{V}_{\mathbf{b}}\mathbf{= 22}\frac{\mathbf{m}}{\mathbf{s}}$$
Εrednia prΔdkoΕΔ wiatru.
Vm(z)=Cr(z)*C0(z)*Vb
Cr(z)β
ββ
Β wspolczynnikΒ chropowatosci
C0(z)β
ββ
wspolczynnikΒ rzezbyΒ terenuβ=β1,β0
Vm(z)β=βCr(z)*Vb
zβ=βΒ 8,β05Β m
Opoleβ ββ Β dzielnicaΒ podmiejska,βΒ kategoriaΒ III
z0β=β0,β3Β m
zminβ=β5Β m
zmaxβ=β200Β m
zminβ<βΒ zβ<βzmax
5Β mΒ β<βΒ 8,β05Β mΒ β<βΒ 200Β mΒ
$$k_{r} = 0,19\left( \frac{z_{0}}{z_{0,\pi}} \right)^{0,07} = 0,19\left( \frac{0,3}{0,05} \right)^{0,07} = 0,215$$
$$C_{r}\left( z \right) = k_{r}*ln\left( \frac{z}{z_{0}} \right) = 0,215*ln\left( \frac{8,05}{0,3} \right) = 0,707$$
$$\mathbf{V}_{\mathbf{m}}\left( \mathbf{z} \right)\mathbf{= 0,707*1,0*22}\frac{\mathbf{m}}{\mathbf{s}}\mathbf{= 15,559}\frac{\mathbf{m}}{\mathbf{s}}$$
Turbulencja wiatru.
zβ=βΒ 8,β05Β m
z0β=β0,β3Β m
zminβ=β5Β m
zmaxβ=β200Β m
zminβ<βΒ zβ<βzmax
k1β=β1,β0
C0(z)β=β1,β0
$$I_{v}\left( z \right) = \frac{k_{1}}{C_{0}\left( z \right)*n\left( \frac{z}{z_{0}} \right)} = \frac{1,0}{1,0*\ln\left( \frac{8,05}{0,3} \right)} = 0,304$$
WartoΕΔ szczytowa ciΕnienia prΔdkoΕci.
$$q_{p}\left( z \right) = \left\lbrack 1 + 7*I_{v}\left( z \right) \right\rbrack*\frac{1}{2}\rho*{V_{m}}^{2}(z)$$
$$\rho = 1,25\frac{\text{kg}}{m^{2}}$$
$$q_{p}\left( z \right) = \left\lbrack 1 + 7*0,304 \right\rbrack*\frac{1}{2}*1,25{*(15,559)}^{2}$$
$$q_{p}\left( z \right) = 473,27\frac{\text{kg}}{{m*s}^{2}} = 473,27\frac{N}{m^{2}} = 0,473\frac{\text{kN}}{m^{2}}$$
CiΕnienie wiatru na powierzchnie zewnΔtrzne.
weβ=βqp(ze)β
*β
Cpe
qp(ze)β
ββ
wartoscΒ szczytowaΒ cisnieniaΒ predkosci
zeβ wysokoΕΔ odniesienia dla ciΕnienia zewnΔtrznego
Cpeβ
ββ
wspolczynnikΒ cisnieniaΒ zewnetrznego,βΒ zalezyΒ odΒ wielkosciΒ obciazonejΒ
powierzchni A
Aβ>β10m2βCpeβ=βCpe,β10
zeβ=βzβ=β8,β05Β m
emin(b,β2h)
bβ=β12,β88Β m
2hβ=β2β
*β
9,β95Β mβ=β19,β9Β m
eβ=β12,β88Β m
$$\frac{e}{10} = 1,288\ m$$
$$\frac{e}{4} = 3,23\ m$$
kierunekΒ wiatru,βΒ Οβ=β0
Ξ±β=β42ββΌβ45
AΒ β>β10m2β=βCpeβ=βCpe,β10
Fβ=βΒ Β Β β +β 0,β7Β Β Β β ββ 0,β0
Gβ=βΒ Β Β β +β 0,β7Β Β Β β ββ 0,β0
Hβ=βΒ Β Β β +β 0,β6Β Β Β β ββ 0,β0
Iβ=βΒ Β Β β +β 0,β0Β Β Β β ββ 0,β2
Jβ=βΒ Β Β β +β 0,β0Β Β Β β ββ 0,β3
dociΔ ΕΌenie
wiβ=βweβ +β wiβ=βqp(ze)β *β Cpeβ +β qp(zi)β *β Cpi
wβ=βweβ=βqp(ze)β *β Cpe
$G:w = 0,473*0,7 = 0,331\frac{\text{kN}}{m^{2}}$
$H:w = 0,473*0,6 = 0,284\frac{\text{kN}}{m^{2}}$
Iβ:βwβ=β0
Jβ:βwβ=β0
KOMBINACJE OBCIΔΕ»EΕ
Ξ¨0,βiβ
ββ
wspolczynnikΒ czesciowyΒ
βΒ strop(kategoria A)βββΞ¨0β=β0,β7
βΒ sniegβββΞ¨0β=β0,β5
βΒ wiatrβββΞ¨0β=β0,β6
ObciΔ ΕΌenie na wiΔΕΊbΔ dachowΔ : | Fk |
f |
Fd |
---|---|---|---|
|
1,421 0,331 0,284 0 0 0,216 |
1,5 1,5 1,5 |
1,918 0,496 0,426 0 0 0,324 |
$$q_{A} = \begin{Bmatrix}
*G_{k}:1,412 + 0,331 + 0,216 = 1,968\frac{\text{kN}}{m^{2}} \\
*G_{d}:1,918 + 0,496 + 0,324 = 2,738\frac{\text{kN}}{m^{2}} \\
*H_{k}:1,412 + 0,284 + 0,216 = 1,921\frac{\text{kN}}{m^{2}} \\
*H_{d}:1,918 + 0,426 + 0,324 = 2,668\frac{\text{kN}}{m^{2}} \\
*I_{k}:1,412 + 0 + 0,216 = 1,637\frac{\text{kN}}{m^{2}} \\
*I_{d}:1,412 + 0 + 0,324 = 2,242\frac{\text{kN}}{m^{2}} \\
*J_{k}:1,412 + 0 + 0,216 = 1,637\frac{\text{kN}}{m^{2}} \\
*J_{d}:1,412 + 0 + 0,324 = 2,242\frac{\text{kN}}{m^{2}} \\
\end{Bmatrix}$$
Reakcje podporowe:
z wiΔΕΊby dachowej:
$$\sum_{}^{}{M_{B} = 0:\ R_{1,k}*8,55 - G_{k}*1,288*\left( 8,606 \right) - H_{k}}*3,687*\left( 6,118 \right) - I_{k}*1,288*\left( 3,631 \right) - J_{k}*2,987*\left( 1,5 \right) + J_{k}*0,7*0,35 = 0$$
R1,βkβ
*β
8,β55β=β79,β736
$$\mathbf{R}_{\mathbf{1,k}}\mathbf{= 9,326}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$
$$\sum_{}^{}{M_{B} = 0:\ R_{1,d}*8,55 - G_{d}*1,288*\left( 8,606 \right) - H_{d}}*3,687*\left( 6,118 \right) - I_{d}*1,288*\left( 3,631 \right) - J_{d}*2,987*\left( 1,5 \right) + J_{d}*0,7*0,35 = 0$$
R1,βdβ
*β
8,β55β=β110,β513
$$\mathbf{R}_{\mathbf{1,d}}\mathbf{= 12,925}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$
$$\sum_{}^{}{M_{A} = 0:\ R_{2,k}*8,55 - I_{k}*3,687*\left( 7,406 \right) - I_{k}}*1,288*\left( 4,919 \right) - H_{k}*3,687*\left( 2,432 \right) - G_{k}*0,588*\left( 0,294 \right) + G_{k}*0,7*0,35 = 0$$
R2,βkβ
*β
8,β55β=β72,β154
$$\mathbf{R}_{\mathbf{2,k}}\mathbf{= 8,439}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$
$$\sum_{}^{}{M_{A} = 0:\ R_{2,d}*8,55 - I_{d}*3,687*\left( 7,406 \right) - I_{d}}*1,288*\left( 4,919 \right) - H_{d}*3,687*\left( 2,432 \right) - G_{d}*0,588*\left( 0,294 \right) + G_{d}*0,7*0,35 = 0$$
R2,βdβ
*β
8,β55β=β72,β154
$$\mathbf{R}_{\mathbf{2,d}}\mathbf{= 8,439}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$
ze stropu:
$$\sum_{}^{}{M_{B} = 0:\ R_{3,k}*3,9 - q_{1,k}*3,285 - q_{2,k}*3,9*1,95 = 0}$$
3,β9β
*β
R3,βkβ=β3,β08β
*β
3,β285β
+β
6,β62β
*β
3,β9β
*β
1,β95
3,β9β
*β
R3,βkβ=β60,β463/:3,β9
$$\mathbf{R}_{\mathbf{3,k}}\mathbf{= 15,5}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$
$$\sum_{}^{}{M_{A} = 0:\ R_{4,k}*3,9 - q_{1,k}*0,615 - q_{2,k}*3,9*1,95 = 0}$$
3,β9β
*β
R4,βkβ=β3,β08β
*β
0,β615β
+β
6,β62β
*β
3,β9β
*β
1,β95
3,β9β
*β
R4,βkβ=β52,β239/:3,β9
$$\mathbf{R}_{\mathbf{4,k}}\mathbf{= 13,39}\frac{\mathbf{k}\mathbf{N}}{\mathbf{m}}$$
$$\sum_{}^{}{M_{B} = 0:\ R_{3,d}*3,9 - q_{1,d}*3,285 - q_{2,d}*3,9*1,95 = 0}$$
3,β9β
*β
R3,βdβ=β4,β62β
*β
3,β285β
+β
9,β084β
*β
3,β9β
*β
1,β95
3,β9β
*β
R3,βdβ=β84,β261/:3,β9
$$\mathbf{R}_{\mathbf{3,d}}\mathbf{= 21,61}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$
$$\sum_{}^{}{M_{A} = 0:\ R_{4,d}*3,9 - q_{1,d}*0,615 - q_{2,d}*3,9*1,95 = 0}$$
3,β9β
*β
R4,βdβ=β4,β62β
*β
0,β615β
+β
9,β084β
*β
3,β9β
*β
1,β95
3,β9β
*β
R4,βdβ=β71,β925/:3,β9
$$\mathbf{R}_{\mathbf{4,d}}\mathbf{= 18,44}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$
ze schodΓ³w:
$$\sum_{}^{}{M_{A} = 0:\ R_{5,k}*3,65 - q_{G,k}*3,65*1,825 = 0}$$
3,β65β
*β
R5,βkβ=β8,β319β
*β
3,β65β
*β
1,β825
3,β65β
*β
R5,βkβ=β55,β415/:3,β65
$$\mathbf{R}_{\mathbf{5,k}}\mathbf{= 15,18}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$
$$\sum_{}^{}{M_{A} = 0:\ R_{5,d}*3,65 - q_{G,d}*3,65*1,825 = 0}$$
3,β65β
*β
R5,βdβ=β11,β529β
*β
3,β65β
*β
1,β825
3,β65β
*β
R5,βdβ=β76,β798/:3,β65
$$\mathbf{R}_{\mathbf{5,d}}\mathbf{= 21,04}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$
ZESTAWIENIE OBCIΔΕ»EΕ:
ObciΔ ΕΌenie przypadajΔ ce na ΕawΔ H1:
H1,βkβ=βR1,βkβ
+β
2β
*β
qw1,βkβ
+β
R5,βkβ
+β
qD,βkβ
*β
(4,05β0,23)mβ
+β
qF,βkβ
*β
1,β05mβ
+β
qH1,βk
$$H_{1,k} = 9,326\frac{kN}{m} + 2*1,521\frac{\text{kN}}{m} + 15,18\frac{\text{kN}}{m} + 3,585\frac{\text{kN}}{m^{2}}*\left( 4,05 - 0,23 \right)m + 9,19\frac{\text{kN}}{m^{2}}*1,05m + 7,5\frac{\text{kN}}{m}$$
$$\mathbf{H}_{\mathbf{1,k}}\mathbf{= 5}\mathbf{8}\mathbf{,}\mathbf{39}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$
H1,βdβ=βR1,βdβ
+β
2β
*β
qw1,βdβ
+β
R5,βdβ
+β
qD,βdβ
*β
(4,05β0,23)mβ
+β
qF,βdβ
*β
1,β05mβ
+β
qH1,βd
$$H_{1,d} = 12,925\frac{\text{kN}}{m} + 2*2,054\frac{\text{kN}}{m} + 21,04\frac{\text{kN}}{m} + 5,209\frac{\text{kN}}{m^{2}}*\left( 4,05 - 0,23 \right)m + 12,422\frac{\text{kN}}{m^{2}}*1,05m + 10,125\frac{\text{kN}}{m}$$
$$\mathbf{H}_{\mathbf{1,d}}\mathbf{= 81,}\mathbf{13}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$
ObciΔ ΕΌenie przypadajΔ ce na ΕawΔ H4:
H4,βkβ=βqw1,βkβ
+β
qD,βkβ
*β
(5β0,23)mβ
+β
qF,βkβ
*β
1,β05mβ
+β
qH4,βk
$$H_{4,k} = 1,521\frac{\text{kN}}{m} + 3,585\frac{\text{kN}}{m^{2}}*\left( 5 - 0,23 \right)m + 9,19\frac{\text{kN}}{m^{2}}*1,05m + 7,5\frac{\text{kN}}{m}$$
$$\mathbf{H}_{\mathbf{4,k}}\mathbf{= 3}\mathbf{5}\mathbf{,}\mathbf{77}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$
H4,βdβ=βqw1,βdβ
+β
qD,βdβ
*β
(5β0,23)mβ
+β
qF,βdβ
*β
1,β05mβ
+β
qH4,βd
$$H_{4,d} = 2,054\frac{\text{kN}}{m} + 5,209\frac{\text{kN}}{m^{2}}*\left( 5 - 0,23 \right)m + 12,422\frac{\text{kN}}{m^{2}}*1,05m + 10,125\frac{\text{kN}}{m}$$
$$\mathbf{H}_{\mathbf{4,d}}\mathbf{=}\mathbf{50}\mathbf{,}\mathbf{07}\frac{\mathbf{\text{kN}}}{\mathbf{m}}$$