dane: |
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S0 = |
1937,480m |
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H0 = |
300,00m n.p.m. |
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iD = |
1,42m |
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HDnpm = |
820,00m |
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iL = |
1,85m |
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HLnpm = |
1044,02m |
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k0 = |
-4mm |
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R = |
6383km |
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p = |
746 mm/Hg |
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t = |
20ºC |
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β = |
7,3830 g |
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Obliczenie poprawki atmosferycznej
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A= |
10 mm/km |
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kA= |
0,019 m |
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S= |
1937,495 m |
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1. a) luster |
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DL= S*cosβ = |
1924,48 m |
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1. b) średni |
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HD = HDnpm - H0 = |
520,00 m |
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HL = HLnpm - H0 = |
744,02 m |
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hD = HD + iD = |
521,42 m |
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hL = HL + iL = |
745,87 m |
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Δh = hL - HD = |
224,45 m |
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Dm = |
1924,450 m |
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1. c) na poziom instrumentu |
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D = |
1924,417 m |
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2. Redukcja na poziom odniesienia odległości z poziomu: |
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2. a) luster |
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d = |
1924,256 m |
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2. b) średniego |
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Δhm = Δh/2 = |
633,645 m |
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d = |
1924,259 m |
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2. c) dalmierza |
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d = |
1924,259 m |
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3. Kontrola (redukcja odległości skośnej S na poziom odniesienia) |
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Σh = HD+iD+HL+iL = |
1267,290 m |
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d = |
1924,259 m |
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4. Obliczenie długości zredukowanej na płaszczyźnie odwzorowawczej układu współrzędnych 2000 |
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m0 = |
0,999923 |
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ym = |
85 km |
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dm = |
1924,111 m |
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Jan Kowalski |
Ćwiczenie nr 2 |
Grupa IVa, numer 12 |
Zestaw nr XI |
Geodezyjne Pomiary Szczegółowe, sem. V |
Oddano: 30 listopada 2010 |
Studia stacjonarne |
Zaliczenie: |