Rozdział 2
,) a) 2NaOH + Zn(N03)2 = Zfi(0H)2 + 2NaN03;
b) Hg2(N03)2 + 2W = Hg2I2 + 2KN03;
c) 3Mg(OH)2 + H4Si04=Mg3(0H)2Si04 + 4H20;
d) Ca(OH)2 + 2H2C03 = Ca(HC03)2 + 2H20;
c) 2FeCl3 + 3(NH4)2S=FcjSj + 6NH4C1;
f) 3K2C03 + Fe2(S04)3 = 3K2S04+Fe2(C03)3.
2) a) MgOHGl + HCI = MgCl2 + H20;
b) Na2HP04 + NaOH = Na3P04 + H20;
c) Ba(H2P04)2+2Ba(OH)2 = BajCPO^ + 4H20;
d) NaHjAs04 + 2NaOH = Na3As04 + 2H20;
e) 2Cr(0H)S04+H2S04 = Cr^SO^j + 2H20;
f) 3Zn2(0H)Aś04, + H3As04 = 2Zn3(As04)2 + 3H20.
3) a) 2AgN03 + (NH^COj = Ag2C03 + 2NH4N03;
b) A1(0H)3 + HjP04 = A1P04 + 3H20;
c) Sń(OH)2 + H2S04 = SnS04 + 2H20;
d) FcS + 2HC1=FeCl2 + HjS;
e) 2A1C13 + 3Ag2S04=Al^SO^ + 6AgCl;
0 Ga(HCD3)2+2HBr = 2H2C03 + CaBr2;
g) 3S02+20r(0H)3 = Cr2(S03)3 + 3H20;
h) C02+ęą(OH)2=CaC03 + H20;
i) 2H3P04 + 3MgC031Mg3(P04}| + 3C02 + 3H20;
j) 3NaOH + (NH4)3P04=Na3P04 + 3NH3 + 3H20.
4) Reakcjami utleniania-rcdukcji są: b), d), g).
5) a) 4H3P03 = 3H3P04 + PH3;
b) 2Tia3 = TiCl2 + TiGl4;
c) 3C+S+2KN03 = N2+3C02+K2S;
d) 3Fe(N03)2 + 4HN03 = NO + 3Ee(N03)3 + 2HjO;
e) 2NaOH + 2F2 = 2NaF + OF2+HjO;
t) 2CuI2 = 2CuI +12;
g) 3H2S30g — 3H2SO4 + 3S02 + 3S;
h) 5HCOOH + 3H2S04 + 2KMn04 = K2S04 + 2MnS04 + 8H20 + 5C02;
i) H2S03 + 2H2S = 3H20 + 3S;
j) v2°5 W 3H2S04 + S = V2(S04)3 + 3H20 + S02;
k) H3V04 + 2HI + 3HC1 = VCI3 +12 + 4H20;
l) 20^6 + 702 = 4C02 + 6H20;
ł) 2Fe(OH)3 + lONaOH + 3C12 = 2Na2Fe04 + 6NaCl + 8H20;
, m) Pt + 4HN03 + 6HCI = H2[PtCI6] + 4N02 + 4H20; n) (NH^CjC^ = 2NH3 + CO + C02 + H20.
6) a) Cu + 4HN03(stężony) = Cu(N03)2 + 2N02 + 2H20;
b) K2Mn04 + 8HC1 = MnQ2 + 2KC1 + 2C12 + 4H20;
. c) 2KBr + a2 = Br2 + 2KC1;
d) 3Zn + KC103 + 3H2S04 = 3ZnS04 + KC1 + 3H20;
e) 8Sb + 3KCI04 + 12H2S04 = 4Sb2(S04)3 + 3KC1 + 12H20;
f) Cr2(S04)3 + 3H202 + IOKOH = 2K2Cr04 + 3K2S04 + 8H20;
g) 2HC1 + K2Sc04 = K2Se03 + Cl2 + H20;
h) 2NaBr + CaOCl2 + H20 = CaCl2 + 2NaOH + Br2;
i) I2 + H2S03 + H20 = H2S04 + 2HI;
j) FeO + 4HN03(slężony) = Fe(N03)3 + N02 + 2H20;
k) 6KI + K2Cr207 + 7H2S04 = 3I2 + 4K2S04 + Cr^SO^j + 7H20;
l) 3NiS + 2HN03 + 6HCI = 3NiCl2 + 2N0 + 4H20 + 3S;
|j 6H2S + 2Cr03 -» Cr2S3 + 3S + 6H20;
m) 3SnS + 4HN03 + H20 = 3H2Sn03 + 4N0 + 3S.
7) a) 3FeCl2 + KN03 + 4HCI = 3FeCI3 + NO + KCI + 2H20;
b) 6HI + K2Cr207 + 4H2S04 = K2S04 + Cr^SO^ + 3I2 + 7H20;
c) 3Mn02 + KCI03 + 6K0H = 3K2Mn04 + KCI + 3H20;
d) 4NH3 + 702 = 4N02 + 6H20;
e) fCajjSO^ +12 + H20 = 2NaI + H2S04;
O Ti02 + 2CaCl2 + 4Na = 2Ca0 + 4NaCI + Ti; g) A1203 + 3C + N2 = 2AIN + 3C0.
8) a) Cr20?" + 6Fe2+ + 14H* = 2CT3* + 6Pto3+ + 7H20;
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