linia wysokiego napiecia

Zadanie z linia:

R=OQ

X=54Q

G=0[iS

B=630

I=800A

Cos(p=0,9

U₂=390000 V

1_2cz = / * cos <9 = 800 * 0,9 = 720A

I_2b =    = V800² -720² = 349A

h =(720 - J349    )A

Z₂=Z_l=R + jX = J54D.

A U_2f =I₂*Z₂ = (720 - y349) * j54 = (18846 + j'3880)F

U_GB = V3A U_2f +U₂= V3(l8846 + y3880) +390000 = (422642 + j6134l)V Y = G + jB = y'630/A

I_gb=Y*U_gb = j630juS *(422642 + y67342) = (-42 + j266)A I_₁ = Ię_Ł + h=(-42 + j266)+ (720 - y349) = (678 -AU_lf = /, * Z, = (678 - j'83)* y'54 = (4482 + y'36612)F

U\ = V3AZ/_ir + U _GB = V3(4482 + y36612)+(422642 + y'67342) = (430405 + y'130756)F

£/, = a/430405² +130756² « 450łF /j = a/678² +83² » 683A