odpowiedzi na kolosa page 023

Przykład - c.d. (rozwiązywanie)

=>    47, — 3 • (—2) = 18    =>    7, =3 A

=> Uj = 3-3-5 (-2) = 9 + 10 = 19V

I₂ = 2 A

'(1 + 3)7, -37„ =18 • (2 + 3)7_n -37, =-Uj Ju = -2

[(1 + 3)7, -37_n =18

Ui=-2

(2 + 3)7„ - 37, =

Przykład - c.d. (prądy gałęziowe)

7, = 2 A

'(1 + 3)7,-37„ =18 >(2 + 3)7,,-37, =-77, Jn = -2

10 + 3)7,-37,, = 18

Ui = -2

(2 + 3)7,, - 37, =-77, 7, =7, =3 A

=>    47, - 3 ■ (-2) = 18 =>    7, =3 A

=>    t/, =33-5 (-2) = 9 + 10 = 19 V

7, = 2 A

7j = 7, -7„ = 3-(-2) = 5 A