386 (4)

-0) 0.80    _n.₀

= ■•••;-- 0.48 e Ai'

7 2.718

^>*^. = -0.12 eAv 72.718

->    /(v<ⁿ) = l

_ę0) _ -n.22

⁴ 7l 8.594

_v0)|

^VA \~^kb

-2.60 e Ar, jy^je (k\k_b) ->    /(wj^l>) =    ......— = 0.85

k-k,

T(V^(I)) =

0.85

krok 2.

	'0.230		1.69"
p(2) _'p{'y(0)p0) „	0.250	, 7^(xr^} ~ 2.69, V^(2) --	0.69
	0.250		- 0.31
	0.043		-11.31

przekątniowe elementy macierzy    _}) :

Diag(Cy^ _]}) - (3.054, 2.706, 2.706. 22.070)

-(2)    1.69    ...

v, - -₇-= 0.97    6 Av

¹    73.054

— (2)    0.69 _A

' = ---= 0.42 e Av

²    7 2.706

vi²⁾ =.--±2L=:_0.19 eAv

72.706

^<^2>)

Kvf) = l

i⁷4²⁾ =    - -2.41 <t Av, |v|^2Jje (/;; A/,)    ->    /(v^<2>) = 1—1—

⁴    722.070    ! ⁴ s    ⁴    £ _ £

= 0.90

przekątniowa macierz tłumienia: T{V⁽²⁾) = Diag(l, 1.1,0.90)

krok 3.

p09 =T(V^,2>)P^(2> =

'0.230		1.62'
0.25	11 JO CT\ N2 < '^3 II	0.62
0.25	A	-0.37
, 0.038		-11.37

	Diag(Cy^ ^) = (3.046, 2.699. 2.699, 24.740)
(3)= L«_ = ^1 -J04(,	0.93 e Ar	- /(v,^0)) = l
-(3) .. 0.62 _ ^2 72.699	0.38 s Ar
7(3) _ -0-37 _ ^3 7 2.699	-0.23 G Ar	- /(v.p) = |
-v{3) ... -11.37 ^t4 724.740	= -2.29 gAv, |v^^3)j6 {k\kf,)	-> «r.f) = L^v:
	T(V^(rs>) = Diag(l, 1.	1, 0.93)

-•(3)1 K

- 0.93

krok 4.

	'0.230		1.58'
	0.25	4" =2.58. V<^4> =	0.58
	0.25	A	- 0.42
	0.036		-1! .42

Diag{Cy^_|o„₍₎) = (3.042, 2.694, 2.694, 26.784)

p(4) _ ^rj^,(y (3) ^p(3) _

ł(v,^(4>) - I f(^⁴⁾) = i

_v7<⁴> =.i^_ = 0.9l e Ar

¹    7.3.042

v<⁴⁾    ^0.35 e Av

²    72.694

“(4) „ -0.42

W =

-0.25 G Av

71694

v|⁴⁾ = -C.¹.— = -2.20 gAv, jv<^4łIe (k\k_b)

⁴    726.7 B4    ! ⁴ i

T(V^{4)) = Diag(l. 1.1,0.95)

((v⁽/^5>) = ^L:

;-(4)j 4 j

T-k_b

^v,{ \~^kb

■■ 0.95

387