z1 prz2 2

K„=5[kN]

EM_b=0 6+3-(4-2)-2-4I-3R_c + (4 + 4)-4 = 0 =s fl<-=H[kN]

Przedział P,B

|W(.r) = -4(kN] |a.v) = 4-2 = 2lkN]

|W(j) = -4lkNJ W) = 2+5 = 7[kN]

j/V(.v) = -4|kN) e<v) = 7-4 = 3[kN]

|m(.v) = 7.v-I6-4(.v-3)=3.«-4

fiV(v) = -4|kN]

«.') =-S[kN]

(W (r) = 3+8(6 -1) = -8x+51

- strona 3 -