Wyniki wyszukiwana dla hasla A b0 image001 B£ST SŁł.LŁH ROHATtCCSavage Surrendcr OtttlOTTT I.WBimage003 B E V E R L YBARTON THE PROTECTORSBLACKW00D S WOMAN^ SiM-es <B~£ Pubtehaó by Sihooed* Boimage003 Murtmy L<i*u*r flnl t*tan wriilna irirara-AfUa fn lt!«. n4 tbtru*N b» Kat i!m» %rfl«»o mimage017 LLOYD BIGGLE, JR. Every society has its own way ot finding a pumshment to tit a crime. no bIMAGE027 ££0,,00 łsn 090.,00 <Qpzxsd> + 0£0„00 łsn 090,.00 <H^oz$d> -000..00 łsn 090. ,0Image163 a = lim AŹ-»0 ~V1 te = lim a^ov(Ą + AQ-v(*i) teImage163 a = lim AŹ-»0 ~V1 te = lim a^ov(Ą + AQ-v(*i) teimage1641 lim a*n —> co g V &> 0YląYl > «0"g <image1641 lim a*n —> co g V &> 0YląYl > «0"g <Image1906 6) lim x-»« lnx = co , lim lnx = -® x-»0+Image1916 .. sin2x lim- x^osin3x lim x-»0 sin2x “2Ć 3x 2 sin3x 3 lim x-»0 sin2x .. 3x 2 ——■ limImage1921 x+2 lim x-»( 1 + x +1 = 42 = 16 ponieważ lim x-»0l 1 + X + 1 = 4 oraz lim (x+2) = 2 x-»0Image1932 1 1 lim xsin— = O gdyż lim x = O i funkcja sin— jest ograniczona, bo x-»0Image1955 g) lim x-»0 X+l)e* cosx h) lim -== x^"“ Vx2 + 1 Wsk. J x dla x > O j-x dlax<0Image2175 V1 _ 2"ł1 . ni b„ (n + 1)! 2" 2 n + 1 lim - 1 + 1Image2228 lim sgnx= lim 1=1 oraz lim sgnx= lim (-1) = —1.zaś sgn 0 = 0. x-»0+Image3030 lim v-»0 f(A + v)~ f(A)-graćf(A)°v MImage3058 3L(0 1 = |jm f((0X3) + t(-\2))-f(0Ą3) dV ’ J t-»0 t ..Image3199 df, , — (x0Jo) dy ljm f(xo,yo + tł)-f(x0ly0) h-»0 Image3200 df, 1 ax |jm f(x0 + fr,y0,ZQ)-f(x0,y0,Zą) h-»0 hWybierz strone: [
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