Wyniki wyszukiwana dla hasla Eqn lines2
Eqn lines2 _ be-cd Sc~^w and tę ae-bd ac-b2
Eqn lines2 _ be-cd Sc~^w and tę ae-bd ac-b2
CHSi-fs eqn[<gcA]u9 pojsnu.iGi.if A qo M2bo{bk9cg s sg^Ł-gmc^ i
egzamin pisemny z matematyki( 01 2009 EGZAMIN PISEMNY Z MATEMATYKI (28.01.2009 r.) Zad.l. Wyznaczyć
Eqn?rycentric P(b^Ą,b2) = avVfi+alVl+a2V2 where a. bi bo +b +b2
Eqn implicit2 -sin(#);ę + cos(ć?)^+(sin(ć?);ę0 -cosfć?)^) = 0
Eqn line n dot v 0 iiL,VL = (a,i)*(^-P0) = a(LXi-Xo)+i(yi-Jo) = f(^i)-f(Ą)) = 0
Eqn parametric2 /*(£) = (jc0 +^cosć??Ły0 +£sin O ]
CHSi-fs eqn[<gcA]u9 pojsnu.iGi.if A qo M2bo{bk9cg s sg^Ł-gmc^ i
Eqn?2 dP0 W0 = P-P0 and ć>0e[-180180° wQ • v <0o|(90|>9(r od(P,S)=d(P,P0)
Eqn?rycentric P(b^Ą,b2) = avVfi+alVl+a2V2 where a. bi bo +b +b2
Eqn Cosine Law c2 =| v-w|2= (v-w)*(v-w) = v* v-2(v*w)+w*w = | v|2 +| w|2 -2| v| | w | cos(ćT) = a2 +
Eqn dp2 d(Ą^) = ax0 +by0 +cz0 +d
Eqn dparam b d(Ą.^))dM |w COS& W*VL W* VL VL VL 2 VL *VL
Eqn implicit2 -sin(#);ę + cos(ć?)^+(sin(ć?);ę0 -cosfć?)^) = 0
Eqn line plane2 1 n.(/j-Ą)
Eqn line direction vector VL = (xv, yv)= Ą-P0 = (JCj --Wi - Jo)
Eqn line n dot v 0 iiL,VL = (a,i)*(^-P0) = a(LXi-Xo)+i(yi-Jo) = f(^i)-f(Ą)) = 0
Eqn parametric2 /*(£) = (jc0 +^cosć??Ły0 +£sin O ]
Eqn seg edge2 (^-Ą).ni<0 => Poą crosses e, from outside to inside => ts is entering (^-Ą).n

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