p11 035

background image

35. Since the rotational inertia of a cylinder is I =

1
2

M R

2

(Table 11-2(c)), its rotational kinetic energy is

K =

1

2

2

=

1

4

M R

2

ω

2

.

For the first cylinder, we have K =

1
4

(1.25)(0.25)

2

(235)

2

= 1.1

× 10

3

J. For the second cylinder, we

obtain K =

1
4

(1.25)(0.75)

2

(235)

2

= 9.7

× 10

3

J.


Document Outline


Wyszukiwarka

Podobne podstrony:
p11 015
12 2005 035 038
p11 086
03 0000 035 02 Leczenie immunosupresyjne sirolimusem
p11 083
p11 046
p13 035
p11 076
p11 058
p11 048
p11 093
p11 017
p11 049
p11 100
p11 022
p11 066
p40 035
p11 044

więcej podobnych podstron