P18 096

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96. Since they are approaching each other, the sound produced (of emitted frequency f ) by the flatcar-

trumpet received by an observer on the ground will be of higher pitch f



. In these terms, we are told

f



− f = 4.0 Hz, and consequently that f



/f = 444/440 = 1.0091. With v

S

designating the speed of the

flatcar and v = 343 m/s being the speed of sound, the Doppler equation leads to

f



f

=

v + 0

v

− v

S

=

⇒ v

S

= (343)

1.0091

1

1.0091

= 3.1 m/s .


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