P15 073

background image

73.

(a) Using Eq. 15-10, we have p

g

= ρgh = 1.21

× 10

7

Pa.

(b) By definition, p = p

g

+ p

atm

= 1.22

× 10

7

Pa.

(c) We interpret the question as asking for the total force compressing the sphere’s surface, and we

multiply the pressure by total area:

p



4πr

2



= 3.82

× 10

5

N .

(d) The (upward) buoyant force exerted on the sphere by the seawater is

F

b

= ρ

w

gV

where V =

4

3

πr

3

.

Therefore, F

b

= 5.26 N.

(e) Newton’s second law applied to the sphere (of mass m = 7.0 kg) yields

F

b

− mg = ma

which results in a =

9.04, which means the acceleration vector has a magnitude of 9.04 m/s

2

and

is directed downward.


Document Outline


Wyszukiwarka

Podobne podstrony:
P15 033
P15 027
P15 034
P15 074
P15 042
P15 045
066 073 Galusid 6621 Nieznany (2)
P15 035
P15 083
p08 073
P15 PRIMOTECQ
P15 018
P15 061
073
P26 073
P15 001
P15 058
P15 044

więcej podobnych podstron