36.

(a) For the minimum (43 cm) case, 9 cubit converts as follows:

(9 cubit)

0.43 m

1 cubit



= 3.9 m .

Andfor the maximum (43 cm) case we obtain

(9 cubit)

0.53 m

1 cubit



= 4.8 m .

(b) Similarly, with 0.43 m

→ 430 mm and0.53 m → 530 mm, we find3.9×10

3

mm and4.8

×10

3

mm,

respectively.

(c) We can convert length anddiameter first andthen compute the volume, or first compute the volume

andthen convert. We proceedusing the latter approach (where d is diameter and  is length).

V

cylinder, min

=

π

4

 d

2

= 28 cubit

3

=



28 cubit

3


0.43 m

1 cubit



3

=

2.2 m

3

.

Similarly, with 0.43 m replacedby 0.53 m, we obtain V

cylinder, max

= 4.2 m

3

.