chap01, p01 020

background image

20. To organize the calculation, we introduce the notion of density (which the students have probably seen

in other courses):

ρ =

m

V

.

(a) We tak e the volume of the leaf to be its area A multiplied by its thickness z.

With density

ρ = 19.32 g/cm

3

and mass m = 27.63 g, the volume of the leaf is found to be

V =

m

ρ

= 1.430 cm

3

.

We convert the volume to SI units:



1.430 cm

3

  1 m

100 cm



3

= 1.430

× 10

6

m

3

.

And since V = A z where z = 1

× 10

6

m (metric prefixes can be found in Table 1-2), we obtain

A =

1.430

× 10

6

m

3

1

× 10

6

m

= 1.430 m

2

.

(b) The volume of a cylinder of length  is V = A where the cross-section area is that of a circle:

A = πr

2

. Therefore, with r = 2.500

× 10

6

m and V = 1.430

× 10

6

m

3

, we obtain

 =

V

πr

2

= 7.284

× 10

4

m .


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