p04 097

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97. Using the same coordinate system assumed in Eq. 4-25, we rearrange that equation to solve for the initial

speed:

v

0

=

x

cos θ

0



g

2 (x tan θ

0

− y)

which yields v

0

= 23 ft/s for g = 32 ft/s

2

, x = 13 ft, y = 3 ft and θ

0

= 55

.


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