P28 094

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94. (Second problem of Cluster)

(a) The loop rule (proceeding counterclockwise around the right loop) leads to

E

2

− i

1

R

1

= 0 (where

i

1

was assumed downward). This yields i

1

= 0.060 A(downward).

(b) The loop rule (counterclockwise around the left loop) gives

(+

E

1

) + (+i

1

R

1

) + (

−i

3

R

3

) = 0

where i

3

has been assumed leftward. This yields i

3

= 0.180 A(leftward).

(c) The junction rule tells us that the current through the 12 V battery is 0.180 + 0.060 = 0.240 A

upward.


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