P28 067

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67. When connected in series, the rate at which electric energy dissipates is P

s

=

E

2

/(R

1

+ R

2

). When

connected in parallel, the corresponding rate is P

p

=

E

2

(R

1

+ R

2

)/R

1

R

2

. Letting P

p

/P

s

= 5, we get

(R

1

+ R

2

)

2

/R

1

R

2

= 5, where R

1

= 100 Ω. We solve for R

2

: R

2

= 38 Ω or 260 Ω.


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